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3 years ago

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Physics

1 answer:

ss7ja [257]3 years ago

7 0

Answer:

Bro where is image Hope you understand me

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Lillle is running. She increases her initial speed of 30 km/h to 40 km/h so she

Alex777 [14]

Answer

$200km {h}^{ - 2}$

Explanation

$Acceleration = \frac{final \: \: \: velocity - initial \: \: velocity }{time} \\ = \frac{(40 - 30)km {h}^{ - 1} }{0.05h} \\ = \frac{10}{0.05} \\ = 200km {h}^{ - 2}$

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6 0

3 years ago

Read 2 more answers

The perimeter of a rectangle can be found using the equation P = 2L + 2W, where P is the perimeter, L is the length, and W is th

sweet [91]

Answer:

The perimeter of the rectangle is 60 units.

Explanation:

The perimeter of a rectangle is given by the equation P = 2L + 2W. With W = 12 units and L = 18 units, substituting the values in the equation above:

P = 2(18 units) + 2(12 units)

P = 36 units + 24 units

P = 60 units

8 0

3 years ago

An object's weight is what to it's mass

oee [108]

object's weight is the independent of mass and gravity .

Weight = mass × gravity

5 0

3 years ago

Suppose a certain jet plane creates an intensity level of 124 dB at a distance of 5.01 m. What intensity level does it create on

Zolol [24]

Answer:71 dB

Explanation:

Given

sound Level $\beta _1=124 dB$

distance $r_1=5.01 m$

From sound Intensity

$\beta =10dB\log (\frac{I_1}{I_0})$

$124=10dB\log (\frac{I_1}{I_0})$

$12.4=\log (\frac{I_1}{I_0})$

$I_1=(1\times 10^{-12})\times 10^{12.4}$

$I_1=2.51 W/m^2$

we know Intensity $I\propto ^\frac{1}{r^2}$

$I_1r_1^2=I_2r_2^2$

$I_2=I_1(\frac{r_1}{r_2})^2$

$I_2=2.51\cdot (\frac{5.01}{2.25\times 10^3})^2$

$I_2=1.24\times 10^{-5} W/m^2$

Sound level corresponding to $I_2$

$\beta _2=10\log (\frac{I_2}{I_0})$

$\beta _2=10\log (\frac{1.24\times 10^{-5}}{1\times 10^{-12}})$

$\beta _2=70.93\approx 71 dB$

6 0

3 years ago

At what water depth will a deep-water wave with a wavelength of 40 meters begin to "feel bottom"? 5 meters 15 meters 20 meters 1

ella [17]

The answer is 20 meters would be the water depth started to feel bottom. This is half of the wavelength. The reason behind this is the wave travels half or the partial of the wavelength underneath the surface. For that reason that is where the wave would be starting to feel the ground.

8 0

3 years ago