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4 years ago

One way to decrease the inertia of an object is to

Physics

2 answers:

ANTONII [103]4 years ago

8 0

The only way to decrease the inertia of an object is to remove some of its mass. (B)

kipiarov [429]4 years ago

7 0

B.

I need to fulfill a character requirement so...$1&:&/&2&&:&;& kwkdndksjwken fjwown fnfj

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Denial cycled at 6 mph for 0.8 h. Then he jogged at 2 mph for

dexar [7]

<h3>Deniel's average speed for the total</h3><h3>distance is 3.6 mph</h3>

Average speed is difined as the total distance travelled divided by the total time required to cover the distance. Mathematically, it is expressed as:

$Ave. Speed = \frac{Total distance }{Total time}$

To obtain the average speed of Daniel, we shall determine the distance travelled in each case. This is illustrated below:

Speed 1 (S₁) = 6 mph

Time 1 (t₁) = 0.8 h.

<h3>Distance 1 (D₁) =? </h3>

$Speed = \frac{Distance}{Time} \\\\S_{1} = \frac{D_{1}}{t_{1}} \\\\6 = \frac{D_{1}}{0.8}$

Cross multiply

D₁ = 6 × 0.8

Speed 2 (S₂) = 2 mph

Time 2 (t₂) = 1.2 h.

<h3>Distance 2 (D₂) =? </h3>

$S_{2} = \frac{D_{2}}{t_{2}}\\\\2 = \frac{D_{2}}{1.2}$

Cross multiply

D₂ = 2 × 1.2

Next, we shall determine the total time. This can be obtained as follow:

Time 1 (t₁) = 0.8 h.

Time 2 (t₂) = 1.2 h.

<h3>Total time (T) =? </h3>

T = t₁ + t₂

T = 0.8 + 1.2

Next, we shall determine the total distance. This can be obtained as follow:

Distance 1 (D₁) = 4.8 mile

Distance 2 (D₂) = 2.4 mile

<h3>Total distance (D) =?</h3>

D = D₁ + D₂

D = 4.8 + 2.4

Finally, we shall determine the average speed of Daniel. This can be obtained as follow:

Total time = 2 h

Total distance = 7.2 mile

<h3>Average speed =?</h3>

$Ave. speed = \frac{Total distance }{Total time} \\\\Ave. speed = \frac{7.2 }{2}$

<h3>Average speed = 3.6 mph</h3><h3 />

Therefore, the average speed of Daniel is 3.6 mph

Learn more: brainly.com/question/680492

5 0

3 years ago

What is the formula that describes the magnitude of impulse on an object?

vladimir1956 [14]

Answer:

Option C.

Impulse = mass × change in velocity

Explanation:

Impulse is defined by the following the following formula:

Impulse = force (F) × time (t)

Impulse = Ft

From Newton's second law of motion,

Force = change in momentum /time

Cross multiply

Force × time = change in momentum

Recall:

Impulse = Force × time

Thus,

Impulse = change in momentum

Recall:

Momentum = mass x velocity

Momentum = mv

Chang in momentum = mass × change in velocity

Change in momentum = mΔv

Thus,

Impulse = change in momentum

Impulse = mass × change in velocity

8 0

3 years ago

?a wire is stretched 30% what is the percentage change in resistance

Marat540 [252]

Answer:

The percentage change in resistance of the wire is 69%.

Explanation:

Resistance of a wire can be determined by,

R = (ρl) ÷ A

Where R is its resistance, l is the length of the wire, A its cross sectional area and ρ its resistivity.

When the wire is stretched, its length and area changes but its volume and resistivity remains constant.

$l_{o}$ = 1.3l, and $A_{o}$ = $\frac{A}{1.3}$

So that;

$R_{o}$ = (ρ $l_{o}$ ) ÷ $A_{o}$ = (ρ × 1.3l) ÷ ( $\frac{A}{1.3}$ )

= (1.3lρ) ÷ ( $\frac{A}{1.3}$ )

= $(1.3)^{2}$ × [(ρl) ÷ A]

= 1.69R (∵ R = (ρl) ÷ A)

$R_{o}$ = 1.69R

Where $R_{o}$ is the new resistance, $l_{o}$ is the new length, and $A_{o}$ is the new area after stretching the wire.

The change in resistance of the wire = $R_{o}$ - R

= 1.69R - 1R

= 0.69R

The percentage change in resistance = $\frac{0.69R}{R}$ × 100

= 0.69 × 100

= 69%

The percentage change in resistance of the wire is 69%.

3 0

3 years ago

When the voltage is high, 100v, how does the filament appear?

Nat2105 [25]

<span>when voltage is high say 100V than the light will be a lot dimmer than design because the light is usually designed to be operated at 240V . If the supply voltage to the bulb is 100V, the filament dissipates 34.7W power and thus the temperature of the filament will be less and hence the bulb does not produce so much light .</span>

8 0

4 years ago

Mario golpea el balón con el pie para lanzárselo a Tamara que está situada a 18 m de distancia. El ángulo de salida del balón es

Brilliant_brown [7]

Answer:

y = 0.99 m

Explanation:

This is a projectile launching exercise, let's start by finding the components of the initial velocity, using trigonometry

cos θ = v₀ₓ / v₀

sin θ = v_{oy} / v₀

v₀ₓ = vo cos θ

v_{oy} = I go sin θ

v₀ₓ = 15 cos 30 = 12.99 m / s

v_{oy} = 15 sin 30 = 7.5 m / s

Let's find the time it takes to travel x = 18 m

x = v₀ₓ t

t = x / v₀ₓ

t = 18 / 12.99

t = 1,385 s

at this point it is at a height of

y = v_{oy} - ½ g t²

y = 7.5 1.385 - ½ 9.8 1.385²

y = 0.99 m

therefore the camera must place the foot 99 cm from the ground

7 0

3 years ago