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Zepler [3.9K]
3 years ago
5

SIMPLE HARMONIC MOTION 1.0 Objective To study simple harmonic motion by observing the motion of a simple pendulum. 2.0 Simple ha

rmonic motion Oscillatory motion is extremely common in nature. Examples include waves (water, sound, earthquake, etc.) and vibrations produced by musical instruments. If the oscillation is characterized by a constant frequency and amplitude (if the motion reproduces itself in a fixed time period T), then the motion is said to be "harmonic." If the oscillation can be described as a sinusoidal function of time and position, the motion is said to be "simple harmonic." Simple harmonic motion (SHM) occurs when for every applied force or torque, there is a restoring force or torque which is proportional to the displacement of the system from its equilibrium position. 2.0.1 Name two real-world examples of harmonic motion. (Hint: Southern California is known for what sort of natural disasters?)
Physics
1 answer:
bagirrra123 [75]3 years ago
8 0

Answer:

the waves in the sea,  leaves of the trees, cables in the bridges, pendulum clock

Explanation:

In nature there are many examples of simple harmonic motion, for example.

* The movement of the waves in the sea is an oscillation movement up and down

* The movement of the leaves of the trees when a wind blows and then stops, but the leaf and branches are oscillating

* The movement of the cables in the bridges, especially in the suspension bridges

* The movement of a pendulum clock

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In a city grid, each block on the east-west streets is 100 meters long. Each block on the north-south streets is 20 meters long.
alex41 [277]

Answer:

72.1 m

Explanation:

Hello!

When the walker walks west, each block he walks will be of 100 m, so the walker walked 4*100m = 400 m west.

Similarly, when the walker walks south, he walks 20 meters per block, therefore, the walker walked 4*20 m = 80 m south.

Since the directions west and south are perpendicular, the distance between the start ad end point is:

d = √(400^2 + 80^2) m = 407.92 m

However the walker traveled 480 m

Therefore, the walker traveled 480 - 407.9 m = 72.1 m farther than the actual distance

8 0
4 years ago
Which material rises from cracks in oceanic crust?
disa [49]

Answer:

trenchs and magma

Explanation:

7 0
3 years ago
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Can someone please help me ASAP
Serggg [28]

Answer:

distance = 6.1022 x10^16[m]

Explanation:

To solve this problem we must use the formula of the average speed which relates distance to time, so we have

v = distance / time

where:

v = velocity = 3 x 10^8 [m/s]

distance = x [meters]

time = 6.45 [light years]

Now we have to convert from light-years to seconds in order to get the distance in meters.

t = 6.45 [light-years]*365[\frac{days}{1light-year}]*24[\frac{hr}{1day}] *60[\frac{min}{1hr}]*60[\frac{seg}{1min} ] =203407200 [s]

Now using the formula:

distance = v * time

distance = (3*10^8)*203407200

distance = 6.1022 x10^16[m]

8 0
3 years ago
The pressure gauge shown below has a spring for which k = 60 N/m, and the area of the piston is 0.50 cm2. Its right end is conne
kicyunya [14]

Answer:

0.025 m

0.059166 m

Explanation:

P = Pressure

A = Area

x = Compression of spring

Force is given by

F=PA\\\Rightarrow F=30000\times 0.5\times 10^{-4}\\\Rightarrow F=1.5\ N

From Hooke's law

F=kx\\\Rightarrow x=\dfrac{F}{k}\\\Rightarrow x=\dfrac{1.5}{60}\\\Rightarrow x=0.025\ m

The spring is compressed 0.025 m

In the second case

F_1=1.5\ N

F_2=101000\times 0.5\times 10^{-4}\\\Rightarrow F_2=5.05\ N

Net force would be

F=F_2-F_1\\\Rightarrow F=5.05-1.5\\\Rightarrow F=3.55\ N

Compression would be

x=\dfrac{F}{k}\\\Rightarrow x=\dfrac{3.55}{60}\\\Rightarrow x=0.059167\ m

The compression of the spring is 0.059166 m

8 0
3 years ago
In a ________ reaction, a complex substance breaks down into simpler substances.
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In a <span>decomposition </span><span>reaction, a complex substance breaks down into simpler substances.
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