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Elena-2011 [213]
2 years ago
8

The loudness of sound is determined by what?

Physics
2 answers:
Alex2 years ago
6 0
The amplitude of a sound wave determines its loudness or volume. A larger amplitude means a louder sound, and a smaller amplitude means a softer sound. In Figure 1 sound C is louder than sound B. The vibration of a source sets the amplitude of a wave.

baherus [9]2 years ago
5 0
The amplitude of a sound<span> wave </span>determines<span> its </span>loudness<span> or volume. A larger amplitude means a louder </span>sound<span>, and a smaller amplitude means a softer </span><span>sound</span>
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How much energy must be added to a bowl of 125 popcorn kernels in order for them to reach a popping temperature of 175°C? Assume
Lisa [10]

Answer:

c) 3176 J

Explanation:

mass of 125 popcorn = 125 x .0001 = . 0125 kg

increase in temperature =  175 - 21 = 154°C

specific heat of popcorn = 1650

heat required to increase temperature

= mass of popcorn x increase in temperature x specific heat

= .0125 x 154 x 1650

=  3176.25 J

8 0
3 years ago
The anther and filament are parts of a flower's:
zaharov [31]
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6 0
2 years ago
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A sodium has an atomic number of 11 and the atomic mass of 23. Determine the its proton, electrons, and neutrons
ioda

The mass number of an element tells us the number of protons AND neutrons in an atom (the two particles that have a measurable mass). Sodium has a mass number of 23amu. Since sodium has 11 protons, the number of neutrons must be 23 – 11 = 12 neutrons.

7 0
3 years ago
In the case of the vacuum tube and movable stopper, what force moves the stopper?
sergejj [24]
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6 0
2 years ago
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Find the fundamental frequency and the next three frequencies that could cause standing-wave patterns on a string that is 30.0 m
maksim [4K]

Answer:

0.786 Hz, 1.572 Hz, 2.358 Hz, 3.144 Hz

Explanation:

The fundamental frequency of a standing wave on a string is given by

f=\frac{1}{2L}\sqrt{\frac{T}{\mu}}

where

L is the length of the string

T is the tension in the string

\mu is the mass per unit length

For the string in the problem,

L = 30.0 m

\mu=9.00\cdot 10^{-3} kg/m

T = 20.0 N

Substituting into the equation, we find the fundamental frequency:

f=\frac{1}{2(30.0)}\sqrt{\frac{20.0}{(9.00\cdot 10^{-3}}}=0.786 Hz

The next frequencies (harmonics) are given by

f_n = nf

with n being an integer number and f being the fundamental frequency.

So we get:

f_2 = 2 (0.786 Hz)=1.572 Hz

f_3 = 3 (0.786 Hz)=2.358 Hz

f_4 = 4 (0.786 Hz)=3.144 Hz

6 0
3 years ago
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