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DerKrebs [107]
3 years ago
15

What is the formula for the compound made from mercury (II) and the nitrate ion.

Chemistry
2 answers:
Kazeer [188]3 years ago
5 0

Answer:

Hg(NO3)2

Explanation:

Hope it helps! :)

tamaranim1 [39]3 years ago
4 0

Answer:

Hg(NO3)2

Explanation:

Hg occurs both as Hg(I) and Hg(II) but nitrate is -1, not -2 We NORMALLY use the smallest set of subscripts but in the case of Hg(I) compounds, most of them are dimeric. Hg2Cl2, Hg2(NO3)2, etc. Note that there also is a mercury(II) nitrate; i.e., Hg(NO3)2. Therefore, although the empirical formula for mercury(I) nitrate is HgNO3, the molecular formula is Hg2(NO3)2 anf I was always encouraged to write the molecular formula instead of the empirical formula.

Hope this helps! Feel free to shoot me any questions <3

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Explanation :

The balanced chemical reaction is:

Ca(NO_3)_2+K_2CO_3\rightarrow CaCO_3+3KNO_3

When calcium nitrate react with potassium carbonate to give calcium carbonate as a precipitate and potassium nitrate.

First we have to calculate the moles of CaCO_3

\text{Moles of }CaCO_3=\frac{\text{Mass of }CaCO_3}{\text{Molar mass of }CaCO_3}

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Mass of CaCO_3 = 0.524 g

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\text{Moles of }CaCO_3=\frac{0.524}{100g/mol}=0.00524mol

Now we have to calculate the concentration of CaCO_3

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Now we have to calculate the concentration of calcium ion.

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