The answer is A temperate zones
Answer:
Explanation:
Analogy:
Who does more work:
Work done is defined as the product of force and distance. Work is done when force moves a body in a particular direction.
In this case, work done is the same thing as the potential energy of the weight.
Work done = potential energy = m x g x h
Mass of weight = 100kg for both Mike and Brian
g is the acceleration due to gravity
h is the height
Since they lifted the weight through the same height;
Work done by Mike = 100gh
Work done by Brian = 100gh
Both Mike and Brian does equal work
Who generates more power:
Power is the rate at which work is done;
Power = 
Power generated by Mike =
= 50gh
Power generated by Brian =
= 33.33gh
We can see that Mike generated more power
Answer:
See attachment for step by step answer and explanation.
Explanation:
Answer:
2/3V
Explanation:
Given that a ball of mass M and speed V collides with another ball of mass 2M and velocity v/2 . After collision they stick together and we need to find their speed after collision . According to Law of Conservation of Momentum , <em>T</em><em>h</em><em>e</em><em> </em><em>t</em><em>o</em><em>t</em><em>a</em><em>l</em><em> </em><em>m</em><em>o</em><em>m</em><em>e</em><em>n</em><em>t</em><em>u</em><em>m</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>s</em><em>y</em><em>s</em><em>t</em><em>e</em><em>m</em><em> </em><em>b</em><em>e</em><em>f</em><em>o</em><em>r</em><em>e</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>a</em><em>f</em><em>t</em><em>e</em><em>r</em><em> </em><em>c</em><em>o</em><em>l</em><em>l</em><em>i</em><em>s</em><em>i</em><em>o</em><em>n</em><em> </em><em>i</em><em>s</em><em> </em><em>c</em><em>o</em><em>n</em><em>s</em><em>t</em><em>a</em><em>n</em><em>t</em><em> </em><em>.</em><em>T</em><em>h</em><em>a</em><em>t</em><em> </em><em>i</em><em>s</em><em> </em><em>;</em>
<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>v</u><u>e</u><u>l</u><u>o</u><u>c</u><u>i</u><u>t</u><u>y</u><u> </u><u>a</u><u>f</u><u>t</u><u>e</u><u>r</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>c</u><u>o</u><u>l</u><u>l</u><u>i</u><u>s</u><u>i</u><u>o</u><u>n</u><u> </u><u>i</u><u>a</u><u> </u><u>2</u><u>/</u><u>3</u><u>V</u><u> </u><u>.</u>