I think it’s 5.0 X 10 8Hz
Answer:
d
Explanation:
First law of thermodynamics
It is also known as energy conservation law.It state that net work in a cyclic process is equal to net heat in that cycle.
From first law
Q=ΔU + W
ΔU = Q - W
ΔU is the change in internal energy of gas.
Q is heat transfer from the system or to the system.
W is the work done by the system or on the system.
If work done on the system then it will be taken as positive and If work done by the system then it will be taken as negative.
If heat taken by system it will taken as positive and If heat rejected by system it will taken as negative.
So Q will be positive if system gains heat and work will be positive if work is done on the system.
Answer:
Explanation:
a ) Let let the frictional force needed be F
Work done by frictional force = kinetic energy of car
F x 107 = 1/2 x 1400 x 35²
F = 8014 N
b )
maximum possible static friction
= μ mg
where μ is coefficient of static friction
= .5 x 1400 x 9.8
= 6860 N
c )
work done by friction for μ = .4
= .4 x 1400 x 9.8 x 107
= 587216 J
Initial Kinetic energy
= .5 x 1400 x 35 x 35
= 857500 J
Kinetic energy at the at of collision
= 857500 - 587216
= 270284 J
So , if v be the velocity at the time of collision
1/2 mv² = 270284
v = 19.65 m /s
d ) centripetal force required
= mv₀² / d which will be provided by frictional force
= (1400 x 35 x 35) / 107
= 16028 N
Maximum frictional force possible
= μmg
= .5 x 1400 x 9.8
= 6860 N
So this is not possible.
A. 90km/h = 25 m/s
W=1/2mv^2
=1/2* 650* 25^2
= 203125(J)
b. v’= 90-50= 40km/h
= 100/9 m/s
W=1/2mv^2
=1/2*650*(100/9)^2
= 40123,45679
