If I understood question correctly,
football 1.3 • 102=132.6
Answer is 132 students participate in football.
GC chromatograms often already have a library of compounds to determine what the substance is. In case the compound cannot be found in the library, one common alternative scientists use when performing is spiking.
Spiking involves gradually increasing the concentration of one specific compound, and looking for a rise in peak height. Here, you can identify which peak corresponds to the compound you spiked. You can do this for each alkene, to determine its peak and retention time.
Answer:
Element Properties
atomic number 47
atomic weight 107.868
melting point 960.8 °C (1,861.4 °F)
boiling point 2,212 °C (4,014 °F)
specific gravity 10.5 (20 °C [68 °F])
oxidation states +1, +2, +3
electron configuration [Kr]4d105s1
hope that helps
Hey there!:
Molar mass:
CHCl3 = ( 12.01 * 1 )+ (1.008 * 1 ) + ( 35.45 * 3 ) => 119.37 g/mol
C% = ( atomic mass C / molar mass CHCl3 ) * 100
For C :
C % = (12.01 / 119.37 ) * 100
C% = ( 0.1006 * 100 )
C% = 10.06 %
For H :
H% = ( atomic mass H / molar mass CHCl3 ) * 100
H% = ( 1.008 / 119.37 ) * 100
H% = 0.008444 * 100
H% = 0.8444 %
For Cl :
Cl % ( molar mass Cl3 / molar mass CHCl3 ):
Cl% = ( 3 * 35.45 / 119.37 ) * 100
Cl% = ( 106.35 / 119.37 ) * 100
Cl% = 0.8909 * 100
Cl% = 89.9%
Hope that helps!
Answer:
Explanation:
Hello there!
In this case, according to the given information, we can set up the appropriate chemical equation when ammonium phosphate reacts with sodium chloride in aqueous solution:
Which stands for a double replacement reaction, whereby ammonium changes phosphate to chloride and sodium changes chloride to phosphate on the products side. In addition, we can balance the aforementioned equation as shown below:
Regards!
