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3 years ago

How many electrons can carbon accept from other atoms while bonding? (1 point)

Physics

2 answers:

solong [7]3 years ago

7 0

Answer: Four electrons

Explanation:

vovangra [49]3 years ago

4 0

Answer:

4 electrons

Explanation:

Carbon atoms have 2 shells and 6 electrons. The first shell contains 2 electrons making it a full shell. The second shell only has 4 electrons. In order to complete the shell, the atom needs a total of 8 electrons. Therefore, while bonding, carbon can accept 4 electrons.

You might be interested in

If a rock has a mass of 0.15 kg on the moon what will its mass be on earth

Dafna11 [192]

The same mass dose not change but weight does

6 0

4 years ago

A particle, whose acceleration is constant, is moving in the negative x direction at a speed of 4.91 m/s, and 12.9 s later the p

Zinaida [17]

Answer:

The particle’s velocity is -16.9 m/s.

Explanation:

Given that,

Initial velocity of particle in negative x direction= 4.91 m/s

Time = 12.9 s

Final velocity of particle in positive x direction= 7.12 m/s

Before 12.4 sec,

Velocity of particle in negative x direction= 5.32 m/s

We need to calculate the acceleration

Using equation of motion

$v = u+at$

$a=\dfrac{v-u}{t}$

Where, v = final velocity

u = initial velocity

t = time

Put the value into the equation

$a=\dfrac{7.12-(-4.91)}{12.9}$

$a=0.933\ m/s^2$

We need to calculate the initial speed of the particle

Using equation of motion again

$v=u+at$

$u=v-at$

Put the value into the formula

$u=-5.321-0.933\times12.4$

$u=-16.9\ m/s$

Hence, The particle’s velocity is -16.9 m/s.

4 0

3 years ago

a ball is launched from the ground with a horizontal speed of 30 m/s and a vertical speed of 30 m/s. what is the balls overall s

padilas [110]

Answer:

30m/ s

Explanation:

this is an example of a projectile, where the path traced by the ball will be a downward parabola.

one must know that the <em>vertical velocity of an object having projectile motion is zero at the top of its trajectory</em> and that the <em>horizontal velocity remains constant throughout</em>.

this means, at the top of the trajectory the <u>ball's overall speed will be equal to its horizontal velocity</u>.

and horizontal velocity is given 30 m/s

hence, overall speed of the ball = 30m/ s

8 0

4 years ago

Why are there warnings about using your cell phone while pumping gas?

kompoz [17]

There are warnings about using your cell phone while pumping gas because cell phone batteries can explode.

<h3>What is pumping gas?</h3>

When the vehicle is not having enough fuel to drive more miles, it needs to be fueled by petrol, diesel or natural gas. This is called pumping gas.

According to the rules of National Fire Protection Association, No one is allowed to use any type of electronic items while pumping gas. So, the cell phone is not allowed.

Phones develop static charge. It is believed that cell phone batteries can explode while pumping gas. It would be a real danger.

Thus, there are warnings about using your cell phone while pumping gas because cell phone batteries can explode.

Learn more about pumping gas.

brainly.com/question/23210418

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4 0

2 years ago

Cylindrical beaker of height 0.100 mm and negligible weight is filled to the brim with a fluid of density rhorhorho = 890 kg/m3k

Nesterboy [21]

Incomplete part of the question

A ball of density ρb = 5000 kg/m3 and volume V = 60.0 cm3 is then submerged in the fluid, so that some of the fluid spills over the side of the beaker. The ball is held in place by a stiff rod of negligible volume and weight. Throughout the problem, assume the acceleration due to gravity is g = 9.81 m/s2 . What is the weight Wb of the ball? Express your answer numerically in newtons.

What is the reading W2 of the scale when the ball is held in this submerged position? Assume that none of the water that spills over stays on the scale. Calculate your answer from the quantities given in the problem and express it numerically in newtons.

What is the force Fr applied to the ball by the rod? Take upward forces to be positive (e.g., if the force on the ball is downward, your answer should be negative). Express your answer numerically in newtons.

The rod is now shortened and attached to the bottom of the beaker. The beaker is again filled with fluid, the ball is submerged and attached to the rod, and the beaker with fluid and submerged ball is placed on the scale.

What weight W3 does the scale now show?

Answer:

(a) 2.94 N

(b) 1 N

(d) 3.42 N

Explanation:

(a)

From the definition of density, it's mass per unit volume hence mass is a product of density and volume. To get weight, we multiply mass by acceleration due to gravity

The weight of the ball is $W=\rho g V$

Where $\rho$ is the density, V is volume and g is acceleration due to gravity

Substituting density for 5000 Kg/m3 and g for 9.8 m/s2 and v for 0.00006 m3 then

$W= 5000 kg/m^{3} * 9.8 m/s^{2} * 0.00006 m^{3}=2.94 N$

(b)

Because the ball is being held up mostly by the rod, the fluid pressure on the bottom of the cylinder is just the same as before.

The scale does not "know" the ball is there at all.

That's why it still reads 1 N.

Therefore, the reading is 1 N

(c)

The buoyant force of the fluid on the ball is equal to the weight of the displaced fluid, namely,

$890 kg/m^{3} * 9.8 m/s^{2} * 0.00006 m^{3} = 0.52 N$

so the force needed for the rod to hold up the ball is 2.94 N - 0.52 N = 2.42 N.

(d)

Now the scale "feels" the weight of the ball,

so the scale reads the weight of the ball

PLUS the weight of the original fluid

MINUS the weight of the fluid that was displaced

= 2.94 N + 1.00 N - 0.52 N = 3.42 N

6 0

3 years ago