The centers for disease control and prevention (CDC) develops recommendations for water fluoridation along with technical requirements for each major compound used.
<h3>What is meant by water fluoridation?</h3>
Almost all water contains some fluoride, but usually not enough to prevent tooth decay. Fluoride can also be added to drinking water supplies as a public health measure for reducing cavities. Water fluoridation is the process of adding fluoride to the water supply so the level reaches approximately 0.7 ppm or 0.7 milligrams of fluoride per liter of water, this is the optimal level for preventing tooth decay.
To learn more about water fluoridation, visit:
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Answer:
Adding a solution containing an anion that forms an insoluble salt with only one of the metal ions.
Explanation:
The student have in solution Ag⁺ and Cu²⁺ ions but he just want to analyze the silver, that means he need to separate ions.
Centrifuging the solution to isolate the heavier ions <em>FALSE </em>Centrifugation allows the separation of a suspension but Ag⁺ and Cu²⁺ are both soluble in water.
Adding enough base solution to bring the pH up to 7.0 <em>FALSE </em>At pH = 7,0 these ions are soluble in water and its separation will not be possible.
Adding a solution containing an anion that forms an insoluble salt with only one of the metal ions <em>TRUE </em>For example, the addition of Cl⁻ will precipitate the Ag⁺ as AgCl(s) allowing its separation.
Evaporating the solution to recover the dissolved nitrates. <em>FALSE</em> . Thus, you will obtain the nitrates of these ions but will be mixed doing impossible its separation.
I hope it helps!
Answer : To calculate the number of moles of copper (II) chloride in 15.0 ml of 0.500 M solution, you have to simply use the given calculation:
15 (ml) X 0.500 (moles) / 1000 (mL) = <span>0.00750 moles of CuCl₂ .
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