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aleksley [76]
3 years ago
11

Nitrogen (atomic number 7) and phosphorus (atomic number 15) belong to group 15 of the Periodic Table. Write the electronic conf

iguration of these two elements. Which of these will be more electronegative? Why?​
Chemistry
2 answers:
Zanzabum3 years ago
8 0

Explanation:

  • The atomic number of nitrogen is 7 , so its electronic configuration will be 2 , 5
  • The atomic number of phosphorus is 15 , so its electronic configuration is 2 , 8, 5

<u>Nitrogen is more electronegative than phosphorus. </u>

<u>Reason</u><u> </u><u>:</u><u>-</u>

<u>From top to bottom down a group, electronegativity decreases</u><u>.</u>

<u>Explanation</u><u> </u><u>:</u><u>-</u>

Number of shell increases down a group, so there is an increased distance b/w the valence electrons and nucleus, or a greater atomic radius.‎ ‎

       Since <u>nitrogen</u> has a smaller atomic radius than <u>phosphorus</u>, the attraction of its nucleus towards the incoming electron is more than phosphorus. So , <u>because of smaller atomic size nitrogen accepts electrons more easily.</u>

scoundrel [369]3 years ago
3 0

Answer:

Electronic configuration of nitrogen: K=2 L=5

Electronic configuration of phosphorus : K = 2 L = 8 M = 5

The element nitrogen will be more electronegative because of the smaller size of its atom. nitrogen accepts electrons more easily.

Explanation:

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8 0
3 years ago
1. Show that heat flows spontaneously from high temperature to low temperature in any isolated system (hint: use entropy change
Inga [223]

Answer:

1 ) Δs ( entropy change for hot block ) = - Q / th  ( -ve shows heat lost to cold block )

Δs ( entropy change for cold block ) = Q / tc

∴ Total Δs = ΔSc + ΔSh

                 = Q/tc - Q/th

2) ΔSdecomposition = Δh / Temp = ( 181.6 * 10^3 / 773 ) = 234.928 J/k

Explanation:

<u>1) To show that heat flows spontaneously from high temperature to low temperature </u>

example :

Pick two(2) solid metal blocks with varying temperatures ( i.e. one solid block is hot and the other solid block is cold )

Place both blocks for time (t ) in an insulated system to reduce heat loss or gain to or from the environment

Check the temperature of both blocks after time ( t ) it will be observed that both blocks will have same temperature after time t ( first law of thermodynamics )

Δs ( entropy change for hot block ) = - Q / th  ( -ve shows heat lost to cold block )

Δs ( entropy change for cold block ) = Q / tc

∴ Total Δs = ΔSc + ΔSh

                 = Q/tc - Q/th

<u>2) Entropy change for Decomposition of mercuric oxide </u>

2HgO (s) → 2Hg(l) + O₂ (g)

Δs = positive

there is transition from solid to liquid and the melting point of mercury ( the point at which reaction will take place ) = 500⁰C

hence ΔSdecomposition = S⁻ Hg  -  S⁻ HgO =

Δh of reaction = 181.6 KJ

Temp = 500 + 273 = 773 k

hence ΔSdecomposition = Δh / Temp = ( 181.6 * 10^3 / 773 ) = 234.928 J/k

8 0
3 years ago
What intermolecular force involves non polar molecules
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Dispersion forces are the only type of intermolecular force operating between non-polar molecules, for example, dispersion forces operate between hydrogen (H2) molecules, chlorine (Cl2) molecules, carbon dioxide (CO2) molecules, nitrogen tetroxide (N2O4) molecules and methane (CH4) molecules.

www.ausetute.com.au/intermof.html


7 0
3 years ago
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