<span>Its D :) evaporation happens all the time, and can only occur at the surface (molecules break off and become gases) whereas boiling is when ANY molecule, whether from the surface, the middle or the bottom can just fly off and become a gas.</span>
Here is the complete question.
Glycerol (C3H8O3), also called glycerine, is widely used in the food and pharmaceutical industries. Glycerol is polar and dissolves readily in water and polar organic solvents like ethanol. Calculate the mole fraction of the solvent in a solution that contains 1.61 g glycerol dissolved in 22.60 mL ethanol (CH3CH2OH; density = 0.7893 g/mol). Round to four significant digits
Answer:
0.9567 mol
Explanation:
Given that:
mass of glycerol = 1.61 g
molar mass of glycerol = 92.1 g/mol
no of mole = 
∴ number of moles of glycerol (
) = 
= 0.0175 mol
Volume of ethanol = 22.60 mL
Density of ethanol = 0.7893 g/mL
Since Density = 
∴ mass of ethanol = density of ethanol × volume of ethanol
mass of ethanol = 0.7893 g/mL × 22.60 mL
mass of ethanol = 17.838 g
Number of moles of ethanol
= 
= 0.387 mole
∴ the mole fraction of the solvent can be determined as:



= 0.95673671199
≅ 0.9567 mol
∴ The mole fraction of the solvent in a solution that contains 1.61 g glycerol dissolved in 22.60 mL ethanol is = 0.9567 mol
Answer:
Zinc sulfide- more soluble in 0.10 M hydrochloric acid solution
Silver chloride- less soluble in 0.10 M hydrochloric acid solution
Lead iodide- same solubility in 0.10 M hydrochloric acid solution as in pure water
Silver hydroxide- same solubility in 0.10 M hydrochloric acid solution as in pure water
Explanation:
Solubility refers to the amount of a substance that dissolves in 1 dm^3 of solvent. Several factors influence the dissolution of solutes in a given solvent. Some substances dissolves at a low pH (in acid solutions) while other dissolve at a low pH (in basic solutions).
For Silver chloride, its solubility decreases in 0.10 M hydrochloric acid solution because of common ion effect when compared to its solubility in pure water.
molecules or protein molecules
Convert the amount of substance in carat to grams.
(5.0 carat) x (0.200 g / 1 carat) = 1 g
The volume of the substance is obtained by dividing the mass by the density,
v = m / d
v = 1 g / (3.51 g/cm³) = 0.2849 cm³
Therefore, the volume of a 5.0 carat diamond is approximately 0.285 cm³.