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maxonik [38]
3 years ago
7

The condensation reaction that forms nucleic acid polymers occurs between a _____ group on one nucleotide and a _____ group on a

second nucleotide.
Chemistry
1 answer:
frozen [14]3 years ago
3 0

Answer:

1=hydroxyl of phosphate

2=hydroxyl

Explanation:

Nucleic acid is the condensation polymer of nucleotide. Nucleotides are link together through ester bond. The hydroxyl group of phosphate on one nucleotide goes to condensation reaction with the hydroxyl group of another nucleotide. This is chain process, a large molecule of nucleic acid is formed. It is also called polynucleotide.

RNA and DNA are formed by the nucleic acid. The building block of nucleic acid made up of three chemicals.

  1. Pentose sugar
  2. Base
  3. Phosphate

Pentose sugar:

The sugars present in DNA and RNA is pentose. In DNA this sugar is deoxyribose while in case of RNA this is ribose sugar. The hydroxyl groups are present on these sugars. Ribose consist of four hydroxyl group while deoxyribose consist of three hyrdroxyl group. These react with phosphoric acid and carboxylic acid and form ester.

Base:

RNA and DNA are consist of four bases:

DNA= Adenine, guanine, thymine, cytosine

RNA= Adenine, guanine, uracil, cytosine

Phosphate:

The inorganic acid H3PO4 is present. The hydroxyl group present on it undergoes the reaction with amines and alcohol to form amide and ester respectively.

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Which of the following elements has the largest electronegativity? A) Bismuth B) Nitrogen C) Potassium D) Arsenic​
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Naturally occurring element X exists in three isotopic forms: X-28 (27.979 amu, 92.21% abundance), X-29 (28.976 amu 4.70% abunda
bezimeni [28]

<u>Answer:</u> The average atomic mass of X is 28.09 amu

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i .....(1)

  • <u>For isotope 1:</u>

Mass of isotope 1 = 27.979 amu

Percentage abundance of isotope 1 = 92.21 %

Fractional abundance of isotope 1 = 0.9212

  • <u>For isotope 2:</u>

Mass of isotope 2 = 28.976 amu

Percentage abundance of isotope 2 = 4.70 %

Fractional abundance of isotope 2 = 0.0470

  • <u>For isotope 3:</u>

Mass of isotope 3 = 29.974 amu

Percentage abundance of isotope 3 = 3.09 %

Fractional abundance of isotope 3 = 0.0309

Putting values in equation 1, we get:

\text{Average atomic mass of X}=[(27.979\times 0.9212)+(28.976\times 0.0470)+(29.974\times 0.0309)]

\text{Average atomic mass of X}=28.09amu

Hence, the average atomic mass of X is 28.09 amu

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