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maxonik [38]
3 years ago
7

The condensation reaction that forms nucleic acid polymers occurs between a _____ group on one nucleotide and a _____ group on a

second nucleotide.
Chemistry
1 answer:
frozen [14]3 years ago
3 0

Answer:

1=hydroxyl of phosphate

2=hydroxyl

Explanation:

Nucleic acid is the condensation polymer of nucleotide. Nucleotides are link together through ester bond. The hydroxyl group of phosphate on one nucleotide goes to condensation reaction with the hydroxyl group of another nucleotide. This is chain process, a large molecule of nucleic acid is formed. It is also called polynucleotide.

RNA and DNA are formed by the nucleic acid. The building block of nucleic acid made up of three chemicals.

  1. Pentose sugar
  2. Base
  3. Phosphate

Pentose sugar:

The sugars present in DNA and RNA is pentose. In DNA this sugar is deoxyribose while in case of RNA this is ribose sugar. The hydroxyl groups are present on these sugars. Ribose consist of four hydroxyl group while deoxyribose consist of three hyrdroxyl group. These react with phosphoric acid and carboxylic acid and form ester.

Base:

RNA and DNA are consist of four bases:

DNA= Adenine, guanine, thymine, cytosine

RNA= Adenine, guanine, uracil, cytosine

Phosphate:

The inorganic acid H3PO4 is present. The hydroxyl group present on it undergoes the reaction with amines and alcohol to form amide and ester respectively.

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Dvinal [7]

Answer : The final volume of gas will be, 26.3 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.974 atm

P_2 = final pressure of gas = 0.993 atm

V_1 = initial volume of gas = 27.5 mL

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 22.0^oC=273+22.0=295K

T_2 = final temperature of gas = 15.0^oC=273+15.0=288K

Now put all the given values in the above equation, we get:

\frac{0.974 atm\times 27.5 mL}{295K}=\frac{0.993 atm\times V_2}{288K}

V_2=26.3mL

Therefore, the final volume of gas will be, 26.3 mL

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A container holds one mole of a gas if the amount of gas is tripled how many molecules of gas will be in the container?
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3 years ago
Calculate the mass of sodium azide required to decompose and produce 2.104 moles of nitrogen. Refer to the periodic table to get
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91 grams of sodium azide required to decompose and produce 2.104 moles of nitrogen.

Explanation:

2NaN3======2Na+3N2

This  is the balanced equation for the decomposition and production of sodium azide required to produce nitrogen.

From the equation:

2 moles of NaNO3 will undergo decomposition to produce 3 moles of nitrogen.

In the question moles of nitrogen produced is given as 2.104 moles

so,

From the stoichiometry,

3N2/2NaN3=2.104/x

= 3/2=2.104/x

3x= 2*2.104

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So, 1.4 moles of sodium azide will be required to decompose to produce 2.104 moles of nitrogen.

From the formula

no of moles=mass/atomic mass

        mass=no of moles*atomic mass

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               = 91 grams of sodium azide required to decompose and produce 2.104 moles of nitrogen.

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