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Inga [223]
3 years ago
13

Balance the following equations

Chemistry
2 answers:
Svetlanka [38]3 years ago
4 0

ANSWER

<em>2Ba + 2HBr → 2BaBr + H2</em>

<em>2BiCl3 + 3H2S → Bi2S3 + 6HCl</em>

<em>Br2 + 2KI → I2 + 2KBr</em>

<em>4Fe + 3O2 → 2Fe2O3</em>

<h3>I HOPE THIS WILL HELP YOU IF NOT THEN SORRY HAVE A GREAT DAY:)</h3>
allochka39001 [22]3 years ago
4 0

Answer:

3Mg _{(s)}  + N _{2(g)} → Mg_{3} N _{2(s)}

Ba _{(s)}  + 2HBr_{(g)}  → BaBr _{2(s)}  + H _{2(g)}

2BiCl_{3(s)} + 3H_{2} S _{(g)}  → Bi _{2} S _{ 3(g)}  + 6HCl _{(g)} \\

Br_{2(g)}  + 2KI _{(g)}  → I _{2(g)}  +2 KBr _{(g)}

4Fe_{(s)}+ 3O_{2(g)}  → 2Fe_{2} O _{3(s)}

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Alex777 [14]

45 m. If each student needs 750 mm of tubing, the teacher should order 45 m of tubing.

a) Find the <em>length in millimetres</em>

Length = 60 students x (750 mm tubing/1 student) = 45 000 mm tubing

b) Convert <em>millimetres to metres </em>

Length = 45 000 mm tubing x (1 m tubing/1000 mm tubing) = 45 m tubing

6 0
3 years ago
Which electrolyte is stronger, NaOH or Ca(OH)2? Why?
nataly862011 [7]

Answer:

NaOH

Explanation:

Look at charge Na has +1 charge and Ca has +2 charge after dissociation . Greater charge Stronger lattice. And as we need weak Lattice, so NaoH is stronger base than Ca(OH)2.

8 0
3 years ago
A 1.0 g sample of a cashew was burned in a calorimeter containing 1000. g of water, and the temperature of the water changed fro
Savatey [412]

Answer:

The correct answer is option C.

Explanation:

1.0 g sample of a cashew :

Heat released on  combustion of 1.0 gram of cashew = -Q

We have mass of water = m = 1000 g

Specific heat of water = c = 4.184 J/g°C

ΔT = 30°C - 25°C = 5°C

Heat absorbed by the water :  Q

Q=1000 g\times 4.184 J/g^oC\times 5^oC=20,920 J

Heat released on  combustion of 1.0 gram of cashew is -20,920 J.

3.0 g sample of a marshmallows  :

Heat released on  combustion of 3.0 g sample of a marshmallows = -Q'

We have mass of water = m = 2000 g

Specific heat of water = c = 4.184 J/g°C

ΔT = 30°C - 25°C = 5°C

Heat absorbed by the water :  Q'

Q'=2000 g\times 4.184 J/g^oC\times 5^oC=41,840 J

Heat released on 3.0 g sample of a marshmallows= -Q' = -41,840 J

Heat released on 1.0 g sample of a marshmallows : q

q =\frac{-Q'}{3} = \frac{-41,840 J}{3}=-13,946.67 J

Heat released on  combustion of 1.0 gram of marshmallows -13,946.67 J.

-20,920 J. > -13,946.67 J

The combustion of 1.0 g of cashew releases more energy than the combustion of 1.0 g of marshmallow.

5 0
3 years ago
A 2.9 kg model rocket accelerates at 15.3 m/s2 with a force of 44 N. Before launch, the model rocket was not moving. After the s
masha68 [24]

Answer:

Newton's first and third law of Motion

Explanation:

The laws applying in the example Newton's first and third laws of Motion.

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7 0
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When c2h4 molecules polymerize, the name of the polymer formed is
Gnoma [55]
<span>When c2h4 molecules polymerize, the name of the polymer formed is (b) Polyethylene. This is because the compound C2H4 is ethylene (common name) or ethene (IUPAC name) and polymerizing it would produce polyethylene. The other names are not applicable for C2H4.

</span>
7 0
3 years ago
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