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Inga [223]
2 years ago
13

Balance the following equations

Chemistry
2 answers:
Svetlanka [38]2 years ago
4 0

ANSWER

<em>2Ba + 2HBr → 2BaBr + H2</em>

<em>2BiCl3 + 3H2S → Bi2S3 + 6HCl</em>

<em>Br2 + 2KI → I2 + 2KBr</em>

<em>4Fe + 3O2 → 2Fe2O3</em>

<h3>I HOPE THIS WILL HELP YOU IF NOT THEN SORRY HAVE A GREAT DAY:)</h3>
allochka39001 [22]2 years ago
4 0

Answer:

3Mg _{(s)}  + N _{2(g)} → Mg_{3} N _{2(s)}

Ba _{(s)}  + 2HBr_{(g)}  → BaBr _{2(s)}  + H _{2(g)}

2BiCl_{3(s)} + 3H_{2} S _{(g)}  → Bi _{2} S _{ 3(g)}  + 6HCl _{(g)} \\

Br_{2(g)}  + 2KI _{(g)}  → I _{2(g)}  +2 KBr _{(g)}

4Fe_{(s)}+ 3O_{2(g)}  → 2Fe_{2} O _{3(s)}

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Also, there is no difference in electronegativity of two nitrogen atoms. Hence, compound formed N_{2} is non-polar covalent in nature.

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When 500 g of water is cooled from 80.0°C to 10.0°C, how much heat energy is lost?
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Dinitrogen tetraoxide, N2O4, decomposes to nitrogen dioxide, NO2, in a first-order process. If k = 1.5 x 103 s-1 at 5 ºC and k =
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Answer:

The activation energy for the decomposition = 33813.28 J/mol

Explanation:

Using the expression,

\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )

Wherem  

k_1\ is\ the\ rate\ constant\ at\ T_1

k_2\ is\ the\ rate\ constant\ at\ T_2

E_a is the activation energy

R is Gas constant having value = 8.314 J / K mol  

Thus, given that, E_a = ?

k_2=4.0\times 10^3s^{-1}

k_1=1.5\times 10^3s^{-1}  

T_1=5\ ^0C  

T_2=25\ ^0C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (5 + 273.15) K = 278.15 K  

T = (25 + 273.15) K = 298.15 K  

T_1=278.15\ K

T_2=298.15\ K

So,

\ln \frac{1.5\times 10^3}{4.0\times 10^3}\:=-\frac{E_{a}}{8.314}\times \left(\frac{1}{278.15}-\frac{1}{298.15}\right)

E_a=-\ln \frac{1.5\times \:10^3}{4.0\times \:10^3}\:\times \frac{8.314}{\left(\frac{1}{278.15}-\frac{1}{298.15}\right)}

E_a=-\frac{8.314\ln \left(\frac{1.5\times \:10^3}{4\times \:10^3}\right)}{\frac{1}{278.15}-\frac{1}{298.15}}

E_a=-\frac{689483.53266 \ln \left(\frac{1.5}{4}\right)}{20}

E_a=33813.28\ J/mol

<u>The activation energy for the decomposition = 33813.28 J/mol</u>

8 0
3 years ago
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