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Contact [7]
3 years ago
10

The weight of the atmosphere above 1 m- of

Physics
1 answer:
mars1129 [50]3 years ago
4 0

Answer:

1.09 kg.m

Explanation:

no need

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3 years ago
What is the maximum value the string tension can have before the can slips? The coefficient of static friction between the can a
Naya [18.7K]

Answer:

T= 38.38 N

Explanation:

Here

mass of can = m = 3 kg

g= 9.8 m/sec2

angle θ = 40°

From figure we see the vertical and horizontal component of tension force T

If the can is to slip - then horizontal component of tension force should become equal to force of friction.

First we find force of friction

Fs= μ R

where

μ = 0.76

R = weight of can = mg = 3 × 9.8 = 29.4 N

Now horizontal component of tension

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==> T= 38.38 N

8 0
3 years ago
Please help, and show steps. Thank you very much!
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t = S/v
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6 0
3 years ago
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