All categories

2 years ago

A moose runs through the woods and covers 825 m North in 118 s. What is the average velocity of the moose?

Physics

1 answer:

weqwewe [10]2 years ago

4 0

Total displacement=825m
Total Time=118s

Average Velocity=Total Displacement/Total Time

$\\ \sf\longmapsto Average\: Velocity=\dfrac{825}{118}$

$\\ \sf\longmapsto Average\:Velocity\approx 8m/s$

You might be interested in

When an object (like a ball) falls, some of its___ energy changes to ___ energy, due to the law of conservation of energy

Alinara [238K]

Answer:

potential, kinetic

Explanation:

pls give brainliest :p

8 0

2 years ago

Suppose a ball had a potential energy of 5 J when you dropped it.What would be it’s kinetic energy just as it hit the ground?

timama [110]

Answer:

Due to Conservation of Energy just as the ball hits the ground it's potential energy is assumed zero

Therefore disregarding air resistance all energy is converted into potential energy.

So KE = PE

(5 J)

4 0

2 years ago

Having greater biodiversity in an ecosystem is beneficial to humans because

11Alexandr11 [23.1K]

Answer:

The answer is A

Explanation:

4 0

2 years ago

Read 2 more answers

Find an equation of the line which is parallel to 2x-3y=6 and passes through the point (6,9)

tatuchka [14]

Step 2: Use the slope to find the y-intercept. Line is parallel so use m = 2/5. 6. Findthe equation of a line passing through the point (8, –9) perpendicular to the line 3x + 8y = 4.

8 0

3 years ago

three condensers are connected in series across a 150 volt supply. The voltages across them are 40,50 and 60 volts respectively,

ioda

Explanation:

Given that,

The voltages across them are 40,50 and 60 volts respectively, and the charge on each condenser is 6×10⁻⁸ C.

(a) Capacitance of capacitor 1,

$C_1=\dfrac{Q}{V_1}\\\\C_1=\dfrac{6\times 10^{-8}}{40}\\\\C_1=1.5\times 10^{-9}\ F\\\\C_1=1.5\ nF$

Capacitance of capacitor 2,

$C_2=\dfrac{Q}{V_2}\\\\C_2=\dfrac{6\times 10^{-8}}{50}\\\\C_2=1.2\times 10^{-9}\ F\\\\C_2=1.2\ nF$

Capacitance of capacitor 3,

$C_3=\dfrac{Q}{V_3}\\\\C_3=\dfrac{6\times 10^{-8}}{60}\\\\C_3=1\times 10^{-9}\ F\\\\C_3=1\ nF$

(b) The equivalent capacitance in series combination is :

$\dfrac{1}{C}=\dfrac{1}{C_1}+\dfrac{1}{C_2}+\dfrac{1}{C_3}\\\\\dfrac{1}{C}=\dfrac{1}{1.5}+\dfrac{1}{1.2}+\dfrac{1}{1}\\\\C=0.4\ nF$

Hence, this is the required solution.

5 0

3 years ago