Answer:
86.14 meters.
Explanation:
Step one:
Given data
velocity of car = 26 m/s
the coefficient of static friction between the tires and the road
µ = 0.4 (kinetic)
Let us take g = 9.81 m/s^2
Required
The distance x = distance in m
We know that
W = F*x (Work is force times distance)
Step two:
Conservation of energy gives
KE = W
Substituting gives
Solving for distance (x) gives
Simplifying
Substitute:
Therefore, the minimum braking distance is 86.14 meters.
<u>169 Kcalories</u> are provided by a portion of food that has 25 grams of carbs, 6 grams of protein, and 5 grams of fat.
Kcalories mean kilo-calories. Basically, kilo-calorie or kcal refers to 1,000 calories. To get the Kcalories of food, you have to add the kcal of carbohydrates, protein, and fat.
Get the product by multiplying the number of grams of carbohydrate, protein, and fat by 4,4, and 9, respectively. So if you want to get the energy or Kcal available from a meal, you must then combine the outcomes.
Simply put it, take note of the following conversions:
So here's how to compute the Kcalories of food that contains 25g carbs, 6g protein, and 5g fat.
1. 25g x 4kcal/g = 100kcal
2. 6g x 4kcal/g = 24kcal
3. 5g x 9kcal/g = 45kcal
4. 100kcal + 24kcal + 45kcal = 169kcal!
Therefore, the food contains 169 kilo-calories!
You might be interested in nutrient density of an orange juice per kcalorie. Look here: brainly.com/question/26495283
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Answer:
0.25m/s
Explanation:
Given parameters
m₁ = 5kg
v₁ = 1.0m/s
m₂ = 15kg
v₂ = 0m/s
Unknown:
velocity after collision = ?
Solution:
Momentum before collision and after collision will be the same. For inelastic collision;
m₁v₁ + m₂v₂ = v(m₁ + m₂)
Insert parameters and solve for v;
5 x 1 + 15 x 0 = v (5 + 15 )
5 = 20v
v = = 0.25m/s