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Anna007 [38]
2 years ago
13

A moose runs through the woods and covers 825 m North in 118 s. What is the average velocity of the moose?

Physics
1 answer:
weqwewe [10]2 years ago
4 0
  • Total displacement=825m
  • Total Time=118s

Average Velocity=Total Displacement/Total Time

\\ \sf\longmapsto Average\: Velocity=\dfrac{825}{118}

\\ \sf\longmapsto Average\:Velocity\approx 8m/s

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The 60.0 kg skier shown below is skiing down a 35.0 degree incline where the magnitude of the friction force is 38.5N
Sunny_sXe [5.5K]

Answer:

a) 4.98m/s²

b) 481.66N

Explanation:

a) Using the Newtons second law of motion

\sum F_x = ma_x\\F_m - F_f = ma_x\\Wsin \theta - F_f = ma_x\\mgsin \theta - F_f = ma_x\\

m is the mass of the object

g is the acceleration due to gravity

Fm is the moving force acting along the plane

Ff is the frictional force opposing the moving froce

a is the acceleration of the skier

Given

m = 60kg

g = 9.8m/s²

\theta = 35°

Ff = 38.5N

Required

acceleration of the skier a

Substituting into the formula;

60(9.8)sin 35^0 - 38.5 = 60a\\588sin35^0 - 38.5 = 60a\\337.26 - 38.5 = 60a\\298.76 = 60a\\a = 298.76/60\\a = 4.98m/s^2\\

Hence the acceleration of the skier is 4.98m/s²

b) The normal force on the skier is expressed as;

N = Wcosθ

N = mgcosθ

N = 60(9.8)cos 35°

N = 588cos 35°

N = 481.66N

Hence the normal force on the skier is 481.66N

5 0
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Ella makes this table to organize her notes on whether atoms gain or lose energy during the changes of state.
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Answer:

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Answer:

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Explanation:

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mestny [16]

Answer:

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