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3 years ago

Which statement is true about a base when it reacts with another substance?

Chemistry

2 answers:

slava [35]3 years ago

8 0

Answer:

Explanation:

I think that:))

soldi70 [24.7K]3 years ago

8 0

The answer is letter C

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At physiological ph, the ionized state of the amino (nh2) group in the r group of lysine is:

kherson [118]

Physiological pH is between 7.37 and 7.43

Lysine is a basic amino acid, which means it has two NH2 groups and one COOH group.

Lysine pKas are: 2.16, 9.06 and 10.05

At low pH (lower than the first pKa, in this case: lower than 2.16) the three groups are protoned. As you increase pH, the first group to lose its proton is the acid group, then the alpha-amino group and then the R-amino group. You will have everything non protoned at a high pH (higher than the highest pKa, in this case: 10.05).

Physiological pH is higher than the lowest pKa and lower than the middle pKa, so it’s the second case: the acid is not protoned, the R-amino is protoned and the alpha amino is protoned.

Protoned aminos are cations: NH3+.

8 0

3 years ago

3.47 g of the hydrated "double salt", ammonium iron (II) sulfate hexahydrate, FeSO4(NH4)2SO4*6H2O was dissolved in 200. mL of wa

Ostrovityanka [42]

Answer:

1.4 × 10^-4 M

Explanation:

The balanced redox reaction equation is shown below;

5Fe2+ + MnO4- + 8H+ --> 5Fe3+ +Mn2+ + 4H2O

Molar mass of FeSO4(NH4)2SO4*6H2O = 392 g/mol

Number of moles Fe^2+ in FeSO4(NH4)2SO4*6H2O = 3.47g/392g/mol = 8.85 × 10^-5 moles

Concentration of Fe^2+ = 8.85 × 10^-5 moles × 1000/200 = 4.425 × 10^-4 M

Let CA be concentration of Fe^2+ = 4.425 × 10^-4 M

Volume of Fe^2+ (VA)= 20.0 ml

Let the concentration of MnO4^- be CB (the unknown)

Volume of the MnO4^- (VB) = 12.6 ml

Let the number of moles of Fe^2+ be NA= 5 moles

Let the number of moles of MnO4^- be NB = 1 mole

From;

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CB= CAVANB/VBNA

CB= 4.425 × 10^-4 × 20 × 1/12.6 × 5

CB = 1.4 × 10^-4 M

7 0

3 years ago

Is water wet????????????????

PilotLPTM [1.2K]

Answer:

no it is dry_____________

6 0

3 years ago

Read 2 more answers

The following chemical equation is not balanced: CO2 + H2 CH4 + H2O When this chemical equation is correctly balanced, what is t

svet-max [94.6K]

The answer is B.2

CO2+4H2 -> CH4 +2H2O

6 0

4 years ago

Read 2 more answers

You react 2.43 grams of magnesium with oxygen from the air according to the following reaction. The final mass of the product, m

Leona [35]

Answer:

The mass of oxygen that reacted is approximately 1.6 grams of oxygen

Explanation:

The given information are;

The mass of magnesium in the reaction = 2.43 grams

The final mass of the magnesium oxide = 4.12 grams

The chemical equation for the reaction is given as follows;

2Mg + O₂ → 2MgO

From which we see that two moles of magnesium, Mg, reacts with one mole of oxygen gas molecule, O₂, to produce two moles of magnesium oxide, MgO

The number of moles of magnesium present, $n_{Mg}$ , is given as follows;

$n_{Mg} = \dfrac{Mass \ of \, magnesium}{Molar \ mass \ of \, magnesium} = \dfrac{2.43}{24.305} \approx 0.1 \ moles$

By the given chemical equation, 2 moles of magnesium reacts with one mole of O₂, therefore;

1 mole of magnesium will react with 1/2 moles of oxygen which is 0.5 moles of oxygen also;

0.1 mole of magnesium will react with 0.05 moles of oxygen

The mass of one mole of oxygen = The molar mass of oxygen = 32 g/mol

The mass of oxygen in the reaction = The number of moles of oxygen × The molar mass of oxygen

The mass of oxygen in the reaction = 0.05 × 32 = 1.6 grams

Also from the molar mass of MgO which is 40.3044 g/mol, we have;

The mass fraction of oxygen = 16/40.3044 = 0.39698 ≈ 0.4

The mass of oxygen = 0.39698 × 4.12 = 1.636 g

Therefore, the mass of oxygen in the reaction is approximately 1.6 grams.

8 0

3 years ago