1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zvonat [6]
4 years ago
5

Why is wavelength the main limiting factor on limit of resolution in light microscopy?

Physics
1 answer:
s344n2d4d5 [400]4 years ago
3 0
The resolution<span> of a </span>microscope is the smallest resolvable distance between two objects. It is <span>defined as the shortest distance between two points on a specimen and the observer can still distinguish them.
</span>The wavelength is a determining and limiting factor in the degree of resolution afforded by the microscope. The relationship between the wavelength and the resolution is:
<span>Shorter wavelengths yield higher resolution </span>and visa versa. 
You might be interested in
The height has a distance of 2.5 seconds to hit the ground what is gravity?
STatiana [176]

Answer:

11 times

Explanatiom:

756 fourty

5 0
3 years ago
A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to en
Nina [5.8K]

We have that for the Question, it can be said that the amount by which the length of the stack decreases is

  • dl'=3.621*10^{-4}m

From the question we are told

A copper (<em>Young's modulus </em>1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each <em>cylinder </em>has a radius of 0.24 cm.

A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack <em>decreases</em>.

Generally the equation for <em>copper </em>cylinder   is mathematically given as

dl=\frac{Flo}{yA}

dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}

dl=1.19064778*10^-^4

Generally the equation for brass<em> </em>cylinder   is mathematically given as

dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}

dl=2.43*10^{-4}

Therefore Total change in length

dl'=1.191*10^-^4+(2.43*10^{-4})

dl'=3.621*10^{-4}m

For more information on this visit

brainly.com/question/23379286

3 0
3 years ago
The ideal mechanical advantage of an inclined plane is 3.5, and its efficiency is 0.6. What is the mechanical advantage of the i
Nadya [2.5K]
Mechanical advantage = ideal mechanical advantage x efficiency = 3.5 x 0.6 = 2.1
The mechanical advantage of the inclined plane is 2.1

7 0
3 years ago
Why do we travel to the moon?​
Art [367]

Answer:By successfully establishing a presence on the Moon, we will enhance life on Earth and prepare to explore the rest of our solar system

Explanation:

6 0
3 years ago
Read 2 more answers
Basic design elements include (Check 7)
myrzilka [38]

Answer: depth, shade, fragrance

Explanation:

4 0
3 years ago
Other questions:
  • If you're swimming underwater and knock two rocks together, you will hear a very loud noise. But if your friend above the water
    7·1 answer
  • What is one way to increase the amplitude of a wave in a medium
    8·1 answer
  • An earthquake 50km from a city produces P and S waves that travel outward at 5000 and 3000 m/s, respectively. Once city resident
    9·1 answer
  • the atomic number of an element is equal to the number of______ contained in one atom of that element​
    12·2 answers
  • Can anyone tell me how to read a micrometer screw gauge I want very clear instructions.
    8·1 answer
  • HELP PLEASE<br>Can someone please explain to me why the answer would be 2.45m/s?
    6·2 answers
  • In order for the eye to see an object, ______________ from the object must be reflected to your eye.
    8·2 answers
  • Hey stob it.<br> Please help me.<br> Cmon help me.<br> Plz.
    6·1 answer
  • SOMEONE HELP ME PLSS​
    12·2 answers
  • Please help me, i would give brainliest
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!