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3 years ago

Why is wavelength the main limiting factor on limit of resolution in light microscopy?

1 answer:

3 0

The resolution of a microscope is the smallest resolvable distance between two objects. It is defined as the shortest distance between two points on a specimen and the observer can still distinguish them.
The wavelength is a determining and limiting factor in the degree of resolution afforded by the microscope. The relationship between the wavelength and the resolution is:
Shorter wavelengths yield higher resolution and visa versa.

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Jane is sliding down a slide. What kind of motion is she demonstrating?

Over [174]

When Jane is sliding down a slide, she is demonstrating translational motion.

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3 years ago

You look at a barometer and see that the air pressure is getting much higher... How will the weather probably change? *

Murljashka [212]

Answer:

The weather will clear up and get sunnier.

Explanation:As weather forecasters monitor air pressure, falling barometer measurements can signal that bad weather is on the way. In general, if a low pressure system is on its way, be prepared for warmer weather with storms and rain. If a high pressure system is coming, you can expect clear skies and cooler temperatures.

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2 years ago

Read 2 more answers

The planet Mars has much less gravitational force that Earth. What would happen if you went to Mars?

vovangra [49]

gravitational force of planet exerted on its object near the surface is known as weight

so here we know that gravitational force of mars is much less than the gravitational force of Earth

So on the surface of mars the Weight of objects must be much less than the weight of object on surface of Earth

so here correct answer must be

D. Your weight would decrease.

6 0

3 years ago

A cylinder is fitted with a piston, beneath which is a spring, as in the drawing. The cylinder is open to the air at the top. Fr

astraxan [27]

Answer:

x = 0.0734 m = 7.34 cm

Explanation:

First we shall calculate the area of the piston:

$Area = \pi radius^2\\Area = \pi (0.028\ m)^2\\Area = 0.00246\ m^2$

Now, we will calculate the force on the piston due to atmospheric pressure:

$Atmospheric\ Pressure = \frac{Force}{Area}\\\\Force = (Atmospheric\ Pressure)(Area)\\Force = (101325\ N/m^2)(0.00246\ m^2) \\Force = F = 249.56\ N$

Now, for the compression of the spring we will use Hooke's Law as follows:

$F = kx\\$

where,

k = spring constant = 3400 N/m

x = compression = ?

Therefore,

x = 0.0734 m = 7.34 cm

8 0

3 years ago

An automobile of mass 1.46 cross times to the power of blank 10 cubed kg rounds a curve of radius 25.0 m with a velocity of 15.0

Vsevolod [243]

The centripetal force exerted on the automobile while rounding the curve is $1.31\times10^4 N$

Explanation:

given that

$Mass\ of\ the\ automobile\ m =1.46\times 10^3 kg\\radius\ of\ the\ curve\ r =25 m\\velocity\ of\ the\ automobile\ v=15m/s\\$

Objects moving around a circular track will experience centripetal force towards the center of the circular track.

$centripetal\ force=mv^2/r\\=1.46\times10^3\times15^2/25\\=1.46\times 10^3\times 225/15\\=1.31\times 10^4 N$

4 0

3 years ago