1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lbvjy [14]
3 years ago
12

A ball is launched with initial speed v from the ground level up a frictionless hill. the hill becomes steeper as the ball slide

s up; however, the ball remains in contact with the hill at all times. using conservation of energy, find the maximum vertical height hmax to which the ball will climb. express your answer in terms of v and g.
Physics
2 answers:
yulyashka [42]3 years ago
8 0

The ball will rise to a maximum height of \boxed{h=\dfrac{v^2}{2g}}.

Explanation:

The kinetic energy of a body is the energy associated with the body by virtue of its motion whereas the potential energy of the body is the amount of energy stored in a body by virtue of its position.

The amount of kinetic energy stored in a body is given by:

\boxed{K=\dfrac{1}{2}mv^2}                                                ...... (1)

Here, K is the kinetic energy, m is the mass and v is the speed of the body.

The potential energy stored in a body as it reaches its maximum height is given as:

\boxed{P=mgh}                                                      ...... (2)

Here, P is the potential energy stored, g is the acceleration due to gravity and h is the height attained by the body.

According to the conservation of energy, the energy can neither be created nor destroyed. It can only be converted from one form to another.

\text{kinetic energy}=\text{potential energy}

Substitute the values of kinetic energy and potential energy and simplify the expression for the maximum height.

\begin{aligned}\dfrac{1}{2}mv^{2}=&mgh_{max}\\h_{max}=&\dfrac{v^2}{2g}\end{aligned}

Therefore, the maximum height attained by the ball as it rises up is \boxed{h_{max}=\dfrac{v^2}{2g}}.

Learn More:

1. The speed of the quarterback after he throws the ball brainly.com/question/1933971

2. Average power created by the force acting on the sled to move it brainly.com/question/465528

3. The work done on the gas to expand at a constant pressure brainly.com/question/2351427

Answer Details:

Grade: Senior School

Subject: Physics

Chapter: Conservation of Energy

Keywords:

Ball is launched, ground level, conservation of energy, kinetic, potential energy, motion, maximum height, in contact with hill, vertical height, in terms of v and g.

frutty [35]3 years ago
4 0
<span>if we take ball then the Kinetic Energy of the ball is ½mV² as it rolls up the slope, the Kinetic Energy is converted to potential energy, PE = mgh. mgh = ½mV² h = V²/2g</span>
You might be interested in
A car speeding down the highway honks its horn, which has a frequency 392 Hz, but a resting bystander hears the frequency 440 Hz
Natali [406]

Answer:

37.42 m/s

Explanation:

We know that apparent frequency, \bar f is given by

\bar f=f\frac {V}{V-V_s} where f is the given frequency in this case 392, V is the speed of sound in air which is given as 343 and V_s is the speed of car which is unknown, \bar f is given as 440 Hz

440=392\times \frac {343}{343-V_s}\\343-V_s=392\times \frac {343}{440}=305.5818182\\V_s=343-305.5818182=37.41818182\approx 37.42 m/s

8 0
2 years ago
On a snowy day, max (mass = 15 kg) pulls his little sister maya in a sled (combined mass = 20 kg) through the slippery snow. max
sesenic [268]

Work done by a given force is given by

W = F.d

here on sled two forces will do work

1. Applied force by Max

2. Frictional force due to ground

Now by force diagram of sled we can see the angle of force and displacement

work done by Max = W_1 = Fdcos\theta

W_1 = 12*5cos15

W_1 = 57.96 J

Now similarly work done by frictional force

W_2 = Fdcos\theta

W_2 = 4*5cos180

W_2= -20 J

Now total work done on sled

W_{net}= W_1 + W2

W_{net} = 57.96 - 20 = 37.96 J

7 0
3 years ago
A jet plane is cruising at 310 m/s when suddenly the pilot turns the engines up to full throttle. after traveling 4.0 km , the j
Inessa [10]
For this problem, we would be using the formula: Vf^2 = Vi^2 + 2ad 
where:
Vf = 400m/s 
Vi = 300m/s 
a = ? 
d = 4.0km 
= 4000m 

400^2 = 300^2 + 2a4000 
a = [ 160000 - 90000 ] / 8000 
a = 8.75m/s^2 
rounding it off to 2 significant figures, will give us 8.8 m/s^2.
4 0
3 years ago
Diffusion occurs faster in gases than in liquids because _____.
jolli1 [7]
The correct answer to go in the blank would be A) The particles are moving faster.
5 0
3 years ago
Read 2 more answers
How to use producer in a sentence science terms
Lunna [17]
A producer makes its own food unlike herbivores who eat the plants.
5 0
3 years ago
Other questions:
  • What is one way you can destroy a magnet’s magnetism?
    13·1 answer
  • An astronomer wants to visualize the relative distances between planets in our solar system. A biologist wants to examine the br
    15·2 answers
  • Katya listed major questions that scientists try to answer when they classify organisms. Her list included the following questio
    5·2 answers
  • Two charged objects of +2Q and +1Q are placed a distance d from one another. The force between the objects in measured as 2F. If
    15·1 answer
  • What is impulse measured in
    10·1 answer
  • The following pairs of surfaces are pushed together with the same amount of force. Between which pair of surfaces will friction
    5·2 answers
  • A patient is administered 20 mg of iodine-131. How much of this isotope will remain in the body after 40 days if the half-life f
    9·1 answer
  • A brick of mass 1.15 kg is attached to a thin (massless) cable and whirled around in a circle in a vertical plane. The circle ha
    5·1 answer
  • 12. A runner at the start of a race generates 250 W of power as he accelerates to 5 m/s. If the runner has a mass of
    12·1 answer
  • What is the gravitational potential energy of a 3 kg ball that is 1 meter above the floor?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!