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Maksim231197 [3]

3 years ago

14

Technician A says that module communications networks are used to reduce the number of wires in a vehicle. Technician B says tha

t a communications network is used to share data from sensors, which can be used by many different modules. Which technician is correct?

1 answer:

Flauer [41]3 years ago

5 0

Answer:

c) both technician A and B

Explanation:

A communication network is a collection of the interconnected networks that are managed to support the transfer of the information form a user in one network location and to a user of the another node.

Are connected as the link and to enable the communication and sharing of the data between the terminals and different modules. Hence both the A and B technicians are equally correct.

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Given the vector A with components Ax = 2.00, Ay = 6.00, the vector B with components Bx = 2.00, By = 22.00, and the vector D =

nekit [7.7K]

Answer:

<em>The magnitude of vector d is 16 and the angle with the x-axis is 270°</em>

Explanation:

<u>Operations With Vectors</u>

Given two vectors in rectangular components:

$\vec a=(ax,ay)\ ,\ \vec b=(bx,by)$

The sum of the vectors is:

$\vec a+\vec b=(ax+bx,ay+by)$

The difference between the vectors is:

$\vec a-\vec b=(ax-bx,ay-by)$

The magnitude of $\vec a$ is:

$|\vec a|=\sqrt{ax^2+ay^2}$

The angle $\vec a$ makes with the horizontal positive direction is:

$\displaystyle \tan\theta=\frac{ay}{ax}\\$

The question provides the vectors:

$\vec a=(2,6)$

$\vec b=(2,22)$

$\vec d=\vec a-\vec b$

Calculate:

$\vec d=(2,6)-(2,22)=(0,-16)$

The magnitude of $\vec d$ is:

$|\vec d|=\sqrt{0^2+(-16)^2}=\sqrt{0+256}=16$

The angle is calculated by:

$\displaystyle \tan\theta=\frac{-16}{0}$

The division cannot be calculated because the denominator is zero. We need to estimate the correct angle by looking at the components of the vector. Since the x-coordinate is zero and the y-coordinate is negative, the vector points downwards (south), thus the angle must be -90° or 270° if the range goes from 0° to 360°.

The magnitude of vector d is 16 and the angle with the x-axis is 270°

4 0

2 years ago

I need help ASAP pleasee!!!

Vera_Pavlovna [14]

Answer: when in doubt go with B

Explanation:

3 0

2 years ago

Read 2 more answers

What is the magnitude of the torque about his shoulder due to the weight of the ball and his arm if he holds his arm straight ou

Lubov Fominskaja [6]

Answer:

The torque about his shoulder is 34.3Nm.

The solution approach assumes that the weight of the boy's arm acts at the center of the boy's arm length 35cm from the shoulder.

Explanation:

The solution to the problem can be found in the attachment below.

6 0

3 years ago

Electromagnetic radiation is:

ruslelena [56]

Hello there.

<span>Electromagnetic radiation is:

</span><span>A- energy that is electric and magnetic
</span>

5 0

3 years ago

"Suppose you tie a rock to the end of a 0.96 m long string and spin it in a horizontal circle with a constant angular velocity o

Ber [7]

Answer:

The mass of the rock is $m = 2.46406 \ kg$

Explanation:

From the question we are told that

The length of the string is $l = 0.96 \ m$

The angular velocity is $w = 20.25 \ rad/s$

The tension on the string is $T = 970 \ N$

Generally the centripetal force acting on the rock is mathematically evaluated as

$T = mlw^2$

making m the subject of the formula

$m = \frac{T}{w^2 * l}$

substituting values

$m = \frac{970}{(20.25^2) * (0.96)}$

$m = 2.46406 \ kg$

8 0

2 years ago