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Maksim231197 [3]
3 years ago
14

Technician A says that module communications networks are used to reduce the number of wires in a vehicle. Technician B says tha

t a communications network is used to share data from sensors, which can be used by many different modules. Which technician is correct?
Physics
1 answer:
Flauer [41]3 years ago
5 0

Answer:

c) both technician A and B

Explanation:

  • A communication network is a collection of the interconnected networks that are managed to support the transfer of the information form a user in one network location and to a user of the another node.
  • Are connected as the link and to enable the communication and sharing of the data between the terminals and different modules. Hence both the A and B technicians are equally correct.
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Find the current in the thin straight wire if the magnetic field strength is equal to 0.00005 T at distance 5 cm. ​
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A

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Prior to the Panama Canal, __________ was a major route between the Atlantic and Pacific oceans.
Bingel [31]
The Rio Grande was the major route prior to the Panama Canal.
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How much heat is given off when 210.0g of water at 0 degrees freezes into ice?
Sergio [31]

In the freezing physical change, when 210.0 g of water a 0 degrees freezes into ice, it gives off 71.0 kJ of heat.

<h3>What is freezing?</h3>

It is a physical change in which liquids give off heat to form solids.

We have 210.0 g of water at 0°C. We can calculate the amount of heat given off when it freezes into ice using the following expression.

Q = ΔH°fus × m

Q = 0.334 kJ/g × 210.0 g = 70.1 kJ

where,

  • Q is the heat released.
  • ΔH°fus is the latent heat of fusion.
  • m is the mass.

In the freezing physical change, when 210.0 g of water a 0 degrees freezes into ice, it gives off 71.0 kJ of heat.

Learn more about freezing here: brainly.com/question/40140

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2 years ago
A rock dropped down a well takes 1.8 s to hit the water. How far below the top of the well is the surface of the water
Brut [27]

Answer: 15.87 m

From the equation of motion:

s=ut+\frac{1}{2}at^2

where, s is the distance traveled, u is the initial velocity, a is the acceleration and t is the time.

The rock free falls under gravity. Initial velocity, u=0 m/s, a=g=9.8m/s^2

It took t=1.8 s for rock to hit the water.

Substitute the values in the given equation:

\Rightarrow s=0+\frac{1}{2}9.8m/s^2\times(1.8s)^2=15.87 m

Hence, the water is 15.87 m below the top level of the well.

3 0
3 years ago
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