Answer : The molar heat of solution of KBr is 19.9 kJ/mol
Explanation :
Mass of KBr = 7.00 g
Molar mass of KBr = 119 g/mole
Heat capacity = 2.72 kJ/K
Change in temperature = 0.430 K
First we have to calculate the moles of KBr.
Now we have to calculate the heat of the reaction.
where,
q = amount of heat = ?
= heat capacity = 
= change in temperature = 0.430 K
Now put all the given values in the above formula, we get:
Now we have to calculate the molar heat of solution of KBr.
where,
n = number of moles of KBr
Therefore, the molar heat of solution of KBr is 19.9 kJ/mol
Answer: option b) 1 dg
Explanation:
1) These are the different equivalences of those quantities:
a) 1 g = 100 cg ⇒ 1 cg = 0.01 g
b) 1 g = 10 dg ⇒ 1 dg = 0.1 g
c) 1 g = 1000 mg ⇒ 1 mg = 0.001 g
d) 1g = 10⁹ g ⇒ 1 ng = 10 ⁻⁹g
2) Now that you have all the masures in grams you can compare:
0.1g > 0.01g > 0.001g > 10 ⁻⁹g
3) So, the largest value is 0.1g which is 1 dg.
Answer:
It was built to house the employees of the Chernobyl Nuclear Power Plants located 4 kilometers away and became the ninth nuclear city in the Soviet Union.
Explanation:
Answer:
No
Explanation:
AgNO₃ + KCl --> AgCl + KNO₃
This reaction is a precipitation reaction. AgCl is formed as a white solid due to its low solubility in water.
<span>Average oxidation state = VO1.19
Oxygen is-2. Then 1.19 (-2) = -2.38
Average oxidation state of V is +2.38
Consider 100 formula units of VO1.19
There would be 119 Oxide ions = Each oxide is -2. Total charge = -2(119) = -238
The total charge of all the vanadium ions would be +238.
Let x = number of of V+2
Then 100 – x = number of V+3
X(+2) + 100-x(+3) = +238
2x + 300 – 3x = 238
-x = 238-300 = -62
x = 62
Thus 62/100 are V+2
62/100 * 100 = 62%
</span>62 % is the percentage of the vanadium atoms are in the lower oxidation state. Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help.
