All categories

2 years ago

Which type of chemical formula is the simplest ratio of atoms in a compound?

Chemistry

1 answer:

Natasha_Volkova [10]2 years ago

6 0

Answer:

empirical formula

This also means that in one mole of iso-octane, there are 8 moles of carbon and 18 moles of hydrogen. The empirical formula is the simplest whole-number ratio of atoms in the compound. For iso-octane, the empirical formula is C4H9. Notice that the molecular formula is twice that of the empirical formula.

You might be interested in

Which shows the weight of an atom?

sammy [17]

Answer:

The atomic mass

Explanation:

3 0

2 years ago

Mendeleev arranged the known chemical elements in a table according to increasing

vesna_86 [32]

Atomic mass. Which is the number of protons and neutrons combined.

8 0

3 years ago

Myth: A dead organism is the same as a nonliving thing in science.<br><br> Fact:<br><br> Evidence:

Ilya [14]

I recently did this assignment!

Instructions: Read each myth (untruth). Reword it to make a factual statement. Then, give two to three reasons why the myth is untrue. Use complete sentences and support your answer with evidence, using your own words.

________________________________________

Answer:

Myth: A dead organism is the same as a nonliving thing in science.

o Fact: In science, dead is the same as nonliving.

o Evidence: Things that are nonliving never had the characteristics of life, and never will. Things that are dead once did have the characteristics of life, but when they die, they lose some of the characteristics. That is why dead and non-living are NOT the same thing.

Hope this helped!

Have an Amazing day!

~Lola

4 0

3 years ago

Read 2 more answers

John dissolves .5g of a white powder in 25g of benzene (FP 5oC) (kf benzene is 5.1) and finds the solution freezes at 3.7oC. Det

navik [9.2K]

Answer:

The compound has a molar mass of 78.4 g/mol

Explanation:

Step 1: data given

Mass of a sample = 0.5 grams

Mass of benzene = 25 grams

Freezing poing = 5 °C

Kf of benzene = 5.1 °C/m

Freezing point solution = 3.7 °C

Step 2: Calculate molality

ΔT = i*Kf*m

⇒with ΔT = the freezing point depression = 5.0 - 3.7 = 1.3 °C

⇒with i = the can't hoff factor = 1

⇒with Kf = the freezing point depression constant of benzene = 5.1 °C/m

⇒with m = the molality

1.3 = 5.1 * m

m = 1.3 / 5.1

m = 0.255 moles /kg

Step 3: Calculate moles

Molality = moles / mass benzene

0.255 molal = moles / 0.025 kg

Moles = 0.255 molal * 0.025 kg

Moles = 0.006375 moles

Step 4: Calculate molar mass of the compound

Molar mass compund = mass / moles

Molar mass compound = 0.5 grams / 0.006375 moles

Molar mass compound = 78.4 g/mol

The compound has a molar mass of 78.4 g/mol

7 0

3 years ago

Cis-3-tert-Butylcyclohexanol has the tert-butyl group in the equatorial position and the alcohol in the ________ position.

Anni [7]

Answer:

Axial

Explanation:

In the most stable conformation of Cis-3-tert-Butylcyclohexanol, the tert-butyl group is at equatorial position and the alcohol group is in the axial position.

If the tert-butyl group is placed in equatorial position, repulsions are minimized. The bulkier the group, the greater the energy difference between the axial and equatorial conformers. Hence for a ring having a bulky substituent, such bulky substituent is better placed in the equatorial position.

The energy difference between the conformers of Cis-3-tert-Butylcyclohexanol is so high that the compound is almost "frozen" in a conformation where the tert-butyl groups are equatorial and the -OH groups are axial. This conformer is more stable by 24 KJ/mol.

8 0

3 years ago