We don't know anything about the amount of distance it travels, but that's okay. The only equation we need here is
velocity(final) = velocity(initial) + acceleration * time
vf = vi + (a * t)
The ball is dropped from rest, so vi = 0 m/s.
We want it so that the ball hits the ground with a final velocity of 60 m/s, so vf = 60 m/s.
We are given the acceleration due to gravity, a = 9.8 m/s^2.
We are solving for the time, t = ?.
Now we just plug in the values.
vf = vi + (a * t)
60 m/s = 0 m/s + (9.8 m/s^2)*(t)
60 = 9.8t
60 / 9.8 = t
t = 6.122 s
Hopefully this is the right answer.
Answer:
Explanation:
To solve this exercise it is necessary to take into account the concepts related to gravitational potential energy, as well as the concept of perigee and apogee of a celestial body.
By conservation of energy we know that,
Where,
Replacing
Our values are given by,
Replacing at the equation,
Therefore the Energy necessary for Sputnik I as it moved from apogee to perigee was
Hij ane les spoona sudhea alldor oakie
The acceleration of gravity on Earth is 9.8 m/s² downward.
This means that gravity adds 9.8 m/s downward to the speed
of a freely falling object every second.
So after 25 sec, it's falling (25 x 9.8m/s) = 245 m/s faster than
it was falling at the beginning of the 25 seconds.
If it dropped from rest (no speed), then its velocity
after 25 seconds is 245 m/s downward.
Acceleration is the rate at which velocity changes.
<span>
Simply equate the two.
</span>
<span>dV / dt = F/m </span>
<span>F*dt = dV * m </span>
<span>
The impulse you give any object (average force * time elapsed) is equal to its change in momentum (mass * change in velocity).</span>
