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anyanavicka [17]
3 years ago
15

2 1.1.4 Quiz: Introduction to Physical Science

Physics
1 answer:
Naily [24]3 years ago
4 0

Answer:

A. 1 J= 1 kg•m²/s²      :)

Explanation:

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Ivan
Take the 1.2 Ah × 3600 = 4320 C
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3 years ago
How long will it take a horse to go from rest to 19 km/hr if it is accelerating at 5<br> km/hr 2 ?
Nataliya [291]

Answer:

I attached a PFD with the answer to your question and roughly 50 others involving acceleration and how to calculate it. This PDF gives you the answers to all the question whilst showing you an in-depth explanation on how they got the answer. Hopefully that helps

Explanation:

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6 0
3 years ago
A spring with spring constant k is suspended vertically from a support and a mass m is attached. The mass is held at the point w
garik1379 [7]

Answer:

The oscillation frequency of the spring is 1.66 Hz.

Explanation:

Let m is the mass of the object that is suspended vertically from a support. The potential energy stored in the spring is given by :

E_s=\dfrac{1}{2}kx^2

k is the spring constant

x is the distance to the lowest point form the initial position.

When the object reaches the highest point, the stored potential energy stored in the spring gets converted to the potential energy.

E_P=mgx

Equating these two energies,

\dfrac{1}{2}kx^2=mgx

\dfrac{k}{m}=\dfrac{2g}{x}.............(1)

The expression for the oscillation frequency is given by :

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

f=\dfrac{1}{2\pi}\sqrt{\dfrac{2g}{x}} (from equation (1))

f=\dfrac{1}{2\pi}\sqrt{\dfrac{2\times 9.8}{0.18}}

f = 1.66 Hz

So, the oscillation frequency of the spring is 1.66 Hz. Hence, this is the required solution.

8 0
4 years ago
Blue light of wavelength 450 nm passes through a diffraction grating with a slit spacing of 0.001 mm and makes an interference p
IceJOKER [234]

Answer:

5 fringes option C

Explanation:

Given:

- The wavelength of blue light λ = 450 nm

- The split spacing d = 0.001 mm

Find:

How many bright fringes will be seen?

Solution:

- The relationship between the wavelength of the incident light, grating and number of bright fringes seen on a screen is derived by Young's experiment as follows:

                                   sin(Q) = n* λ / d

Where, n is the order of bright fringe. n = 0, 1, 2, 3, ....

- We need to compute the maximum number of fringes that can be observed with the given condition and setup. Hence we will maximize our expression above by approximating sin(Q).

                                   sin(Q_max) = 1

                                   Q_max = 90 degree

- Hence, we have:

                                    n = d / λ

- plug values in            n = 0.001 *10^-3 / 450*10^-9

                                    n = 2.222

- Since n order number can only be an integer we will round down our number to n = 2.

- Hence, we will see a pair of bright fringes on each side of central order fringe.

- Total number of fringes = 2*2 + 1 = 5 fringes is total ... Hence, option C

8 0
3 years ago
What is the distance magnification formula
damaskus [11]

Does that help I hope IT does you probably just have to write the 1st sentence.

7 0
4 years ago
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