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Marina CMI [18]
3 years ago
12

A wave has an amplitude of 0.0800 m and is moving .33 m/s . One oscillator in the wave takes 0.115 s to go from the lowest point

in its motion to the highest point. Find the period of the wave.
Physics
1 answer:
garik1379 [7]3 years ago
6 0

Answer:

0.230 s

Explanation:

The period is the length of time from one peak to the next.  If it takes the oscillator 0.115 s to go from the lowest point to the highest point, then it takes another 0.115 s to return to the lowest point.  So the period is 0.115 + 0.115 = 0.230 seconds.

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Answer:-24,5m/s

Explanation: what we have here is a UALM with these gravity as acceleration (-9.8 m/s^2). The initial position is 25 m and initial speed is 10m/s.

Speed and gravity are increasing in the opposite direction, speed upwards and gravity downwards, while the position is also upwards, depending on your reference system.

The first thing I need to know is the maximum high it will reach.

Hmax=- S(0)^2/2g=

S= speed.

0= initial

G= gravity

Hm= 100/19,6= 5.1 m

So, the ball will go 5,1 m higher than the initial position, and from there it will fall free.

Then, I need to know how long it takes to fall. For that we use UALM equation:

X(t)= X(0) + S(0)*t + (A*t^2)/2.

X: position

S: speed

A: acceleration

T:time

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0 = 25m +10*t -(9.8 * t^2)/2

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30,1=25+10*t-4,9*t^2

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A= (St-S0)/t

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