2 years ago

For what interval(s) is the function negative?

1 answer:

7 0

Answer:

The negative regions of a function are those intervals where the function is below the x-axis. It is where the y-values are negative (not zero). y-values that are on the x-axis are neither positive nor negative. The x-axis is where y = 0.

Step-by-step explanation:

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Which expression is equivalent to 2x^2 +7x+4

rodikova [14]

Answer:

11x + 4

Step-by-step explanation:

First find 2 to the power of 2. Which is multiplying 2 by its self so 4x.

Then add the 4x to 7x which is 11x

Then since 4 doent have an x it cant be combined so thats the answer: 11x + 4

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3 years ago

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In the following equations, what would you multiply the second equation to

exis [7]

-3 because you could eliminate the 3x by subtracting it by 3x

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2 years ago

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vivado [14]

$2\dfrac{1}{5}+1\dfrac{1}{10}=2+\dfrac{1}{5}+1+\dfrac{1}{10}=(2+1)+\left(\dfrac{1}{5}+\dfrac{1}{10}\right)\\\\=3+\left(\dfrac{1\cdot2}{5\cdot2}+\dfrac{1}{10}\right)=3+\left(\dfrac{2}{10}+\dfrac{1}{10}\right)=3+\dfrac{2+1}{10}=\boxed{3\dfrac{3}{10}}$

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3 years ago

How do you divided 3 by 927

Nostrana [21]

The answer 309
You jus literally divide 927/3 and get 309

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3 years ago

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If <img src="https://tex.z-dn.net/?f=t_n" id="TexFormula1" title="t_n" alt="t_n" align="absmiddle" class="latex-formula"> = 11n−

4vir4ik [10]

$\displaystyle\bf\\t_n=11n-6\\\\t_1=11\cdot1-6=11-6=\boxed{\bf5}\\\\t_{10}=11\cdot10-6=110-6=\boxed{\bf104}\\\\t_{n+1}-t_n=11(n+1)-6-(11\cdot n-6)=11n+11-6-11n+6=\boxed{\bf11}$

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3 years ago