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Tresset [83]
3 years ago
13

What is density?And It's SI unit.​

Physics
1 answer:
borishaifa [10]3 years ago
5 0

Answer:

Density is defined as mass per unit volume. Hence its SI unit is: kg/m3

Explanation:

pls mark me branilest

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Help me find the word of this definition
Andrej [43]

Answer:

Replication

Explanation:

<em>The process of running multiple trials for each measurement during an experiment and finding the average is referred to as </em><em>replication.</em>

Replication is one of the attributes of good measurements/experiments because it reduces variability and increases the accuracy of the outcome. It also ensures that relevant statistical analysis can be carried out on the data collected via replicative measurements.  

4 0
3 years ago
How are galaxies organized and distributed within the universe
den301095 [7]
The galaxies aren't distributed randomly throughout the universe but they are grouped in gravitationally bound clusters.
3 0
3 years ago
Read 2 more answers
A string attached to an airborne kite is maintained at an angle of 41 degrees with the horizontal. If a total of 152 m of string
satela [25.4K]

Answer:

The  horizontal displacement is  Adj  =  114.71 \ m

Explanation:

From the question we are told that  

    The  angle at which the string is maintained is  \theta  =  41 ^o

      The length of string reeled in is  l  = 152 \ m

     

Using the SOHCAHTOA formula

   We have that the hypotenuse(Hyp) is  l  =  152

Hence the  horizontal displacement of the kite  which is the Adjacent(Adj)  can be evaluated as  

     cos \theta  =  \frac{Adj}{Hyp }

substituting values

     cos(41)  =  \frac{Adj}{152}

=>   Adj  =  114.71 \ m

3 0
3 years ago
In part one of this experiment, a 0.20 kg mass hangs vertically from a spring and an elongation below the support point of the s
statuscvo [17]

To solve this problem it is necessary to apply the concepts related to Hooke's Law as well as Newton's second law.

By definition we know that Newton's second law is defined as

F = ma

m = mass

a = Acceleration

By Hooke's law force is described as

F = k\Delta x

Here,

k = Gravitational constant

x = Displacement

To develop this problem it is necessary to consider the two cases that give us concerning the elongation of the body.

The force to keep in balance must be preserved, so the force by the weight stipulated in Newton's second law and the force by Hooke's elongation are equal, so

k\Delta x = mg

So for state 1 we have that with 0.2kg there is an elongation of 9.5cm

k (9.5-l)=0.2*g

k (9.5-l)=0.2*9.8

For state 2 we have that with 1Kg there is an elongation of 12cm

k (12-l)= 1*g

k (12-l)= 1*9.8

We have two equations with two unknowns therefore solving for both,

k = 3.136N/cm

l = 8.877cm

In this way converting the units,

k = 3.136N/cm(\frac{100cm}{1m})

k = 313.6N/m

Therefore the spring constant is 313.6N/m

3 0
3 years ago
Why are the orbits of planets only nearly circular and not perfectly circular?
Galina-37 [17]

Explanation:

this is my answer this is helpful for you

7 0
3 years ago
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