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DedPeter [7]
4 years ago
6

Why is the following situation impossible? A student's dormitory room measures 3.7 m by 3.7 m, and its ceiling is 2.6 m high. Af

ter the student completes his physics course, he displays his dedication by completely wallpapering the walls of the room with the pages from his physics textbook which has 960 pages of text on 480, 0.21 m × 0.28 m sheets. He even covers the door and window
Physics
2 answers:
Oksanka [162]4 years ago
5 0
<span>I believe the that it is impossible for him to cover the whole room. Because SA of the room is 65.86 and the SA of a piece of paper is .0588. 
And by multiplying it by  480 we get 28.24 and that what makes it impossible to cover the whole room.</span>
torisob [31]4 years ago
4 0

Answer:

Surface area of walls (38.48 meter squares)>the total surface area of 480 sheets(28.224  meter squares) .Thus the given situation is not possible .

Explanation:

Given dimensions of walls of room are

length L=3.7 m

breadth B= 3.7 m

Height H= 2.6 m

Therefore surface area S= 2H(L+B)

=>S= 2\times 2.6(3.7+3.7)m^{2}=38.48m^{2}

Dimensions of sheets of book

length l=0.21 m

breadth b=0.28 m

Surface area of single sheet , A=lb=0.21\times 0.28 m^{2} = 0.0588 m^{2}

Therefore total surface area of 480 sheets of book is

A_t=480A=480\times 0.0588 m^{2}=28.224 m^{2}

Since S> A_t  surf,i.e.,ace area of walls of room is much greater than the total surface area of sheets of book, it is not possible to completely wallpaper the walls of the room with pages from his physics text .

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Which statements describe elliptical galaxies? *Select the two correct answers.*
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Two Earth satellites, A and B, each of mass m = 940 kg , are launched into circular orbits around the Earth's center. Satellite
-Dominant- [34]

Answer:

The required work done is 6.5\times10^{9}\ J

Explanation:

Given that,

Mass of each satellites = 940 kg

Altitude of A = 4500 km

Altitude of B = 11100 km

We need to calculate the potential energy

Using formula of potential

U_{A}=-\dfrac{Gm_{A}m_{E}}{r_{A}}

Put the value into the formula

U_{A}=-\dfrac{6.67\times10^{-11}\times940\times5.98\times10^{24}}{6.38\times10^{6}+4.50\times10^{6}}

U_{A}=-3.44\times10^{10}\ J

We need to calculate the potential energy

Using formula of potential

U_{B}=-\dfrac{Gm_{B}m_{E}}{r_{A}}

Put the value into the formula

U_{B}=-\dfrac{6.67\times10^{-11}\times940\times5.98\times10^{24}}{6.38\times10^{6}+11.10\times10^{6}}

U_{B}=-2.14\times10^{10}\ J

We need to calculate the value of k_{A}

Using formula of k_{A}

k_{A}=-\dfrac{1}{2}U_{A}

Put the value into the formula

k_{A}=\dfrac{1}{2}\times3.44\times10^{10}

k_{A}=1.72\times10^{10}\ J

We need to calculate the value of k_{B}

Using formula of k_{B}

k_{B}=-\dfrac{1}{2}U_{B}

Put the value into the formula

k_{B}=\dfrac{1}{2}\times2.14\times10^{10}

k_{B}=1.07\times10^{10}\ J

We need to calculate the work done

Using formula of work done

W=\Delta K+\Delta U

W=(k_{B}-k_{A})+(U_{B}-U_{A})

W=(-\dfrac{U_{B}}{2}+\dfrac{U_{A}}{2})+(U_{B}-U_{A})

W=\dfrac{1}{2}(U_{B}-U_{A})

Put the value into the formula

W=\dfrac{1}{2}\times(-2.14\times10^{10}+3.44\times10^{10})

W=6.5\times10^{9}\ J

Hence, The required work done is 6.5\times10^{9}\ J

7 0
3 years ago
A positive charge is placed at rest at the center of a region of space in which there is a uniform electric field. (A uniform fi
Harlamova29_29 [7]

Answer:

.D.It will decrease because the charge will move in the direction of the electric field

Explanation:

<em>which there is a uniform electric field. (A uniform field is one whose strength and direction are the same at all points within the region.) What happens to the electric potential energy of the positive charge, after the charge is released from rest in the uniform electric field?A. It will remain constant because the electric field is uniform.B.It will decrease because the charge will move in the opposite direction of the electric field.C.It will remain constant because the charge remains at rest.D.It will decrease because the charge will move in the direction of the electric field.E.It will increase because the charge will move in the direction of the electric field.</em>

solution

The potential energy decreases, converted to kinetic energy

The charge will feel a force in the direction of the electric field (F=Eq) and thus it will accelerate with

a constant acceleration. (Just like releasing an object above the earth's surface - constant acceleration,

at least until it hits something.)

tus te answer will be

.D.It will decrease because the charge will move in the direction of the electric field

7 0
3 years ago
A research vessel is mapping the bottom of the ocean using sonar. It emits a short sound pulse called "ping" downward. The frequ
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Answer:

d = 4180.3m

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Explanation:

Given that

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t=5.63s

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d=\frac{1485*5.63}{2}\\d= 4180.3m

wavelengt of sound is \lambda = v/f

= (1485)/(5920)

= 0.251 m

7 0
3 years ago
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