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Karo-lina-s [1.5K]
3 years ago
13

Name an acid which is highly corrosive and should never be tested by mouth.​

Physics
2 answers:
Vitek1552 [10]3 years ago
5 0

Answer:

We all know that HCI is highly corrosive mineral acid. It's produced naturally in our (Human being) Stomach

It (HCI) is produced by the gastric glands in stomach. HCI activates the enzyme Pepsin and creates an acidic medium which kills the bacteria which might have entered while digestion & also making it simpler for further digestion.

HCI does not harm our stomach because the gastric gland also produces Mucus which helps in preventing the damage of inner wall (layer) of stomach from the action of this Acid.

Aleksandr [31]3 years ago
3 0
Hydrofluoric acid and sodium hydroxide because these acids can eat through your bone and tissue
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A bird is flying in a room with a velocity field of . Calculate the temperature change that the bird feels after 9 seconds of fl
Korvikt [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The temperature change is \frac{dT}{dt} = 1.016 ^oC/m

Explanation:

From the question we are told that

   The velocity field with which the bird is flying is  \vec V =  (u, v, w)= 0.6x + 0.2t - 1.4 \ m/s

   The temperature of the room is  T(x, y, u) =  400 -0.4y -0.6z-0.2(5 - x)^2 \  ^o C

    The time considered is  t =  10 \  seconds

    The  distance that the bird flew is  x  =  1 m

 Given that the bird is inside the room then the temperature of the room is equal to the temperature of the bird

Generally the change in the bird temperature with time is mathematically represented as

      \frac{dT}{dt} = -0.4 \frac{dy}{dt} -0.6\frac{dz}{dt} -0.2[2 *  (5-x)] [-\frac{dx}{dt} ]

Here the negative sign in \frac{dx}{dt} is because of the negative sign that is attached to x in the equation

 So

       \frac{dT}{dt} = -0.4v_y  -0.6v_z -0.2[2 *  (5-x)][ -v_x]

From the given equation of velocity field

    v_x  =  0.6x

    v_y  =  0.2t

     v_z  =  -1.4

So

\frac{dT}{dt} = -0.4[0.2t]  -0.6[-1.4] -0.2[2 *  (5-x)][ -[0.6x]]    

substituting the given values of x and t

\frac{dT}{dt} = -0.4[0.2(10)]  -0.6[-1.4] -0.2[2 *  (5-1)][ -[0.61]]      

\frac{dT}{dt} = -0.8 +0.84 + 0.976  

\frac{dT}{dt} = 1.016 ^oC/m  

5 0
3 years ago
Voices of swimmers at a pool travel 400 m/s through the air and 1,600 m/s underwater. The wavelength changes from 2 m in the air
Nata [24]

The frequency of a sound is whatever frequency leaves the source. It doesn't change.

Voiced of swimmers at the pool don't change frequency in or out of the water. Only their speed and wavelength change.

5 0
3 years ago
Read 2 more answers
The company where you work has obtained and stored five lasers in a supply room. You have been asked to determine the intensity
VikaD [51]

Answer:

a)  I = 5.79 10⁵ W/m² , b)  I = 2.58 10² W / m², c)   I = 8.03 10³ W / m² , d)     I = 5.3 10⁶ W / m², e)  I = 9 10¹ W / m² , f)  D> A> C> B> E

Explanation:

The intensity is defined as the power per unit area

       I = P / A

The area of ​​a circle is

      A = π r²

Laser A

Power P = 2.2 W

Diameter d = 2.9 mm = 2.9 10⁻³ m

Let's calculate

Area

      A =  π d² / 4

     A =  π (2.2 10⁻³)²/4

     A = 3.80 10⁻⁶ m²

Let's calculate the intensity

     I = 2.2 / 3.80 10⁻⁶

     I = 0.579 10⁶ W / m²

     I = 5.79 10⁵ W/m²

Laser B

The electric field is E = 440 V / m

Intensity average is

      I = E B / 2 μ₀

The relationship of the fields with the speed of light

      E / B = c

The intensity  

       I = EE / 2 μ₀ c

       I = 440² / (2 4π 10⁻⁷ 3 10⁸)

      I = 1.936 105/750

      I = 2.58 10² W / m²

Laser C

The magnetic field amplitude B = 8.2 10⁻⁶ T

      I = c / 2μ₀  B²

      I = 3 10⁸/2 4π 10⁻⁷ (8.2 10⁻⁶)²

      I = 8.03 10³ W / m²

Part D

Diameter d = 1.8 mm = 1.8 10⁻³ m

The radius is r = d / 2 = 0.9 10⁻³ m

The force is F = 9.0 10⁻⁸ N

The radiation pressure is on a reflective surface is

         P = 2S / c

         I = S =P c / 2

The definition of pressure is

         P = F / A

          I = F c / 2 A

          I = 9.0 10⁻⁸ 3 10⁸ / (2π (0.9 10⁻³)²)

          I = 5.3 10⁶ W / m²

Part E

Average energy density

         u = 3.0 10⁻⁷ J / m³

          I = S = c u

          I = 3 10⁸ 3.0 10⁻⁷

          I = 9 10¹ W / m²

Part F

Sort in descending order

The order is

  D> A> C> B> E

7 0
3 years ago
If a substance can not be separated physically or chemically it is
Leya [2.2K]
If a substance can not be separated physically or chemical it is an element.

5 0
3 years ago
A transverse sinusoidal wave on a string has a period T= 25.0ms and travels in the negative x direction with a speed of 30.0 m/s
aleksandrvk [35]

The wave is equation with the given conditions is y = 0.02 cos ( 0 )

<u>Given data</u>

period T= 25.0ms

speed of 30.0 m/s

t = 0

x = 0

transverse position of 2.00cm

speed of 2.0 m/s = v

<h3>writing the wave function </h3>

frequency f = 1 / T

f = 1 / 25

f = 0.04Hz

Angular velocity = ω = 2 * pi * f

ω = 2 * pi * 0.04

ω = 0.251

wave number K = ω / v

k = 0.251 / 2

k = 0.126

The wave equation

y = A cos (  kx + ωt )

this is equivalent to

y = 0.02 cos ( 0.126 * 0 + 0.251 * 0 )

y = 0.02 cos ( 0 )

Read more on wave equation here: brainly.com/question/28167443

#SPJ4

6 0
1 year ago
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