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3 years ago

Round 9094 to the nearest thousand

Mathematics

1 answer:

rjkz [21]3 years ago

4 0

Answer:

Assuming the number is 9.094 the answer is 9.094 If it is whole number it is 9000

Step-by-step explanation:

The tens place is .0

The Hundreds place is .09

The thousands place is .094

if you are talking about whole numbers: it's 9000

When rounding, 5 and above it is rounded up, and 4 and below is rounded down.

So for this problem you only need to look one place to the right.

9<u>0</u>94 Because that number is 0 that means you round down.

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2 years ago

What happens to the function f(x)=(x−1)2+1 when it becomes f′(x)=2((x−1)2+1)?

Ymorist [56]

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2 years ago

Read 2 more answers

Write the following numbers correct to one significant figure a) 7682 b)0.07682

malfutka [58]

Answer:

a) 8 x 10^3 or 8000

b) 8 x 10^-2 or .08

Explanation: Refer to a guide on rounding sig figs

3 0

3 years ago

The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of

ser-zykov [4K]

Answer:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$ , for $r_{1} = 0$

Step-by-step explanation:

The general form of quintic-order polynomial is:

$p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f$

According to the statement of the problem, the polynomial has the following roots:

$p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)$

Then, some algebraic handling is done to expand the polynomial:

$p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)$

$p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x$

If $r_{1} = 0$ , then:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$

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2 years ago

How to rationalize the denominator of sqrt(a)/sqrt(a)-2

aivan3 [116]

Answer:

√a(√a + 2) a - 2√a

----------------- = -----------------

a - 4 a - 4

Step-by-step explanation:

I am assuming that by "sqrt(a)/sqrt(a)-2" you meant:

√a

----------

√a - 2

To rationalize the denom., multiply numerator and denom. of this fraction by the conjugate of √a - 2, which is √a + 2:

√a(√a + 2)

-----------------

a - 4

3 0

3 years ago