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2 years ago

Select the correct answer.

Physics

1 answer:

Ilia_Sergeevich [38]2 years ago

8 0

Pretty sure it is B.
Because inertia is a tendency to do nothing or remain unchanged.

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1) Write Newton's three laws of motion (20 points). 2) Define acceleration (20 points). 3) Write the Month and Day of the Assign

vaieri [72.5K]

Answer:

Hey

I have no idea when YOUR assignment is due.

Newtons 1rst law:

An object that has constant motion will remain at that speed unless acted on by an external force.

Newtons 2nd law:

F=ma (force=mass*acceleration)

Newtons 3rd law:

when a force is applied to an object, there will be an opposite but equal reaction.

Acceleration:

How much your speed increases/decreases per unit of time.

I wrote all that^

4 0

3 years ago

The default unit of rotational speed is 'radians per second' or 'rad/s'. If a someone sits at the edge of a 5m radius carousel a

Blizzard [7]

The rotational speed of the person is 0.4 rad/s.

<h3>Rotational speed (rad/s)</h3>

The rotational speed of the person in radian per second is calculated as follows;

v = ωr

where;

v is linear speed in m/s
r is radius in meters
ω is speed in rad/s

ω = v/r

ω = 2/5

ω = 0.4 rad/s

Thus, the rotational speed of the person is 0.4 rad/s.

Learn more about rotational speed here: brainly.com/question/6860269

7 0

3 years ago

Cellus

WINSTONCH [101]

Answer:

Its initial position was 471 m.

Explanation:

We have,

Final position of the object is 327 m

Displacement of the object is -144 m

It is required to find its initial position. The difference of final and initial position is equal to the displacement of the object. So,

$d=\text{final position}-\text{initial position}\\\\-144=327-\text{initial position}\\\\\text{initial position}=327+144\\\\\text{initial position}=471\ m$

So, its initial position was 471 m.

5 0

4 years ago

To get off a frozen lake, a 70 kg person removes his shoe of mass 0.175 kg and throws it horizontally away from the shore at a v

MakcuM [25]

Answer:

the person will be in the shore at 10.73 minutes after launch the shoe.

Explanation:

For this we will use the law of the lineal momentum.

$L_i = L_f$

Also,

L = MV

where M is de mass and V the velocity.

replacing,

$M_i V_i = M_{fp}V_{fp} + M_{fz}V_{fz}$

wher Mi y Vi are the initial mass and velocity, Mfp y Vfp are the final mass and velocity of the person and Mfz y Vfz are the final mass and velocity of the shoe.

so, we will take the direction where be launched the shoe as negative. then:

(70)(0) = (70-0.175)( $V_fp$ ) + (0.175)(-3.2m/s)