Answer:
the correct answer is d
Explanation:
The laws of mechanics are related
F = m a
the acceleration of the body is given by the kinematics
a =
v =
substituting
a = \frac{d2x}{dt^2}
F = m
Therefore, in order to obtain the force (interaction of a body), continuous curves are needed and derivable from the position and the speed, for which all change in the trajectory of a body must be smooth where smooth is understood to have until the second derived.
Consequently the correct answer is d
Answer:
1.38 s
Explanation:
Use the free falling formula
T = √(L)/ g
T = √18.75/9.8
T = 1.38 s
Answer:
Explanation:
a) Using the equation of motion
S = ut + 1/2gt²
S is the distance of fall
g is the acceleration due to gravity
t is the time taken
Given S = 12.0m, g = 9.81m/s^2, un= 0m/s
12 = 0+1/2(9.81)t²
12 = 4.905t²²²
t² = 12/4.905
t² = 2.446
t = √2.446
t = 1.56secs
b) To determine how fast is the frog falling at this point, we need to calculate the speed of the frog. Using the equaton v = u+gt
v = 0+9.81(1.56)
v = 15.34m/s
Hence the frog is falling at the rate of 15.34m/s
Assume a 2D plane and both the birds start at origin. +X is east, -X is west, +Y is North, -Y is South.
So, after travel position of bird1 is (-2.8, 2.7) and bird2 is (-2.7,2.8);
slope of bird1 is 2.8/2.7
slope of bird2 is 2.7/2/8
Now we have two solpes b1 and b2
formula = (b2-b1)/(1+b1*b2);
Answer:
![g(h)=9.81943\ m/s^2](https://tex.z-dn.net/?f=g%28h%29%3D9.81943%5C%20m%2Fs%5E2)
Explanation:
The given function is
![g(h)=\dfrac{3.99\times 10^{14}}{(6.374\times 10^6+h)^2}](https://tex.z-dn.net/?f=g%28h%29%3D%5Cdfrac%7B3.99%5Ctimes%2010%5E%7B14%7D%7D%7B%286.374%5Ctimes%2010%5E6%2Bh%29%5E2%7D)
Now h = the height from the surface of the Earth
Here the building is 458 m tall
![g(458)=\dfrac{3.99\times 10^{14}}{(6.374\times 10^6+458)^2}](https://tex.z-dn.net/?f=g%28458%29%3D%5Cdfrac%7B3.99%5Ctimes%2010%5E%7B14%7D%7D%7B%286.374%5Ctimes%2010%5E6%2B458%29%5E2%7D)
![\Rightarrow g(458)=9.81943\ m/s^2](https://tex.z-dn.net/?f=%5CRightarrow%20g%28458%29%3D9.81943%5C%20m%2Fs%5E2)
So,
![g(h)=9.81943\ m/s^2](https://tex.z-dn.net/?f=g%28h%29%3D9.81943%5C%20m%2Fs%5E2)