The amount of gravitational pull an object experiences is its a mass b density

Physics

1 answer:

nata0808 [166]2 years ago

7 0

The amount of gravitational pull an object experiences is its mass

<h3>What is Weight ?</h3>

Weight can be define as gravitational pull an object. It is a product of mass and acceleration due to gravity. That is, W = mg. It is measured in Newton (N)

The amount of gravitational pull an object experiences is its mass and not density because the weight of an object depend on its mass and acceleration due to gravity.

W = mg

where

W = weight

m = mass

g = acceleration due to gravity

Therefore, the amount of gravitational pull an object experiences is its mass

Learn more about Weight here: brainly.com/question/19753744

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Why does fluid pressure exist?

zubka84 [21]

Answer:

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Explanation:

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3 years ago

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garik1379 [7]

First we need to convert everything into SI units.

The initial volume of the gas is (keeping in mind that $1 L = 0.001 m^3$ :
$V_i = 5.0 L = 0.005 m^3$

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The final pressure of the gas is (keeping in mind that $760 mmHg = 1 atm=1.01 \cdot 10^5 Pa$ )
$p_f = 1240 mmHg = 1.65 \cdot 10^5 Pa$

At constant temperature, the product between pressure and volume of the gas is constant, so we can write
$p_i V_i = p_f V_f$

from which we find the final volume of the gas:
$V_f = \frac{p_i V_i}{p_f} = \frac{(1.52 \cdot 10^5 Pa)(0.005 m^3)}{1.65 \cdot 10^5 Pa} =0.0046 m^3 = 4.6 L$

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3 years ago

Adam and Natalie push on a cart using 150 N of force.The cart does not move.What is static friction on the cart?

Roman55 [17]

When force is applied on an object the object will not slide

So here object will remain in equilibrium after applying the force

So in this case the condition of equilibrium is maintained due to friction force that is applied on the object.

So here for equilibrium be can say

$F_{net} = 0$