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miss Akunina [59]
3 years ago
15

It took a squirrel 0.50\,\text s0.50s0, point, 50, start text, s, end text to run 5.0\,\text m5.0m5, point, 0, start text, m, en

d text leftward to a nearby tree while maintaining a constant acceleration. The squirrel was running 15\,\dfrac{\text m}{\text s}15 s m ​ 15, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction leftward when it reached the tree.
Physics
2 answers:
Alexandra [31]3 years ago
7 0

Answer:

-5

Explanation:

khan academy

STALIN [3.7K]3 years ago
3 0

Answer:

-5.0m/s

Explanation:

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Calculate their densties in Si unit.<br>200mg,0.0004m​
Kryger [21]

Question: calculate their densties in Si unit.

200mg,0.0004m​³

Answer:

0.5 kg/m³

Explanation:

Applying,

D = m/V........................ Equation 1

Where D = density, m = mass, V = volume.

From the question,

Given: m = 200 mg = (200/1000000) kg = 2.0×10⁻⁴ kg, V = 0.0004 m³ = 4.0×10⁻⁴ m³

Substitute these values into equation 1

D = (2.0×10⁻⁴ kg)/(4.0×10⁻⁴)

D = 2/4

D = 0.5 kg/m³

Hence the density in S.I unit is 0.5 kg/m³

3 0
2 years ago
The ball X has a known position at 3 different times, each 1 second apart. The positions of the ball are (1.8,2.2)m, (4.4,4.8)m,
Mandarinka [93]

Answer:

Explanation:

From the position coordinates given , it appears that the ball moves simultaneously along x and y direction.

Displacement along x direction in one second = 4.4 - 1.8 = 2.6 m

So velocity along x direction V_x = \frac{2.6}{s}

Similarly velocity along y direction V_y(1) =  \frac{2.6}{s}

In the next phase velocity changes both in x and y direction.

velocity in x - direction V_x(2) = [tex]\frac{2}{s}[/tex

Velocity in Y- direction V_y(2) = [tex]\frac{3.1}{s}[/tex

Acceleration in x direction = change of velocity in x direction

= ( 2 - 2.6 ) = -.6 m s⁻²

Acceleration in y direction = ( 3.1 - 2.6 ) = 0.5 m s⁻²

Total acceleration =\sqrt{( -.6 )² + ( .5 )²}

= .78 ms⁻²

6 0
3 years ago
A simple pendulum is used to determine the acceleration due to gravity at the surface of a planet. The pendulum has a length of
SVEN [57.7K]

Answer:

Acceleration due to gravity is 20 m/sec^2

So option (E) will be correct answer

Explanation:

We have given length of the pendulum l = 2 m

Time period of the pendulum T = 2 sec

We have to find acceleration due to gravity g

We know that time period of pendulum is given by

T=2\pi \sqrt{\frac{l}{g}}

2=2\times 3.14 \sqrt{\frac{2}{g}}

0.3184= \sqrt{\frac{2}{g}}

Squaring both side

0.1014= {\frac{2}{g}}

g=19.71=20m/sec^2

So acceleration due to gravity is 20 m/sec^2

So option (E) will be correct answer.

8 0
3 years ago
At a given time of​ day, the ratio of the height of an object to the length of its shadow is the same for all objects. If a 4​-f
katrin2010 [14]

Answer:35.2 ft

Explanation:

Given

height of stick =4 ft

shadow length =2.8 ft

Angle of elevation of sun is

tan\theta =\frac{4}{2.8}

let the height of tree be h

as \thetawill remain same thus

tan\theta =\frac{h}{24.64}

\frac{4}{2.8}=\frac{h}{24.64}

h=35.2 ft

8 0
3 years ago
Your cousin is moving into an apartment in San Francisco. This apartment is on a street that is angled at 25∘ above the horizont
Vesnalui [34]

Answer:

70

Explanation:

5 0
2 years ago
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