Answer:
Lol, you should do Nate, Bobby, Cindy, Joe, and Beth
Jk, if you want to be series and probably not fail go for these:
If it wants types of small/average stars, then go with
Small star names:
OGLE-TR-122B
Gliese 229 B
TRAPPIST-1
Teegarden's Star
Luyten 726-8 (A and B)
Proxima Centauri
Wolf 359 111400
Ross 248
Barnard's Star
CM Draconis B
Ross 154 167000
CM Draconis A
Kapteyn's Star
41kg object that is moving east at 5 m s
Answer:
Explanation:
1) Hypermetropia (better known as Farsighted- this is why nearby objects seem blurry for him)
2) In such instances, image are typically formed farther from the near point
3) Such defects are quite common so there are common procedures such as using convex lens which can restore the sight to normal.
Because atoms is something that pops or has bubbles in it
The statement about pointwise convergence follows because C is a complete metric space. If fn → f uniformly on S, then |fn(z) − fm(z)| ≤ |fn(z) − f(z)| + |f(z) − fm(z)|, hence {fn} is uniformly Cauchy. Conversely, if {fn} is uniformly Cauchy, it is pointwise Cauchy and therefore converges pointwise to a limit function f. If |fn(z)−fm(z)| ≤ ε for all n,m ≥ N and all z ∈ S, let m → ∞ to show that |fn(z)−f(z)|≤εforn≥N andallz∈S. Thusfn →f uniformlyonS.
2. This is immediate from (2.2.7).
3. We have f′(x) = (2/x3)e−1/x2 for x ̸= 0, and f′(0) = limh→0(1/h)e−1/h2 = 0. Since f(n)(x) is of the form pn(1/x)e−1/x2 for x ̸= 0, where pn is a polynomial, an induction argument shows that f(n)(0) = 0 for all n. If g is analytic on D(0,r) and g = f on (−r,r), then by (2.2.16), g(z) =
