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Strike441 [17]
3 years ago
8

Define the term work​

Physics
2 answers:
weeeeeb [17]3 years ago
6 0

Answer:

Work is the product of force and distance moved in the direction of force.

The Standard International unit is joules.

BY GERALD GREAT

bagirrra123 [75]3 years ago
5 0

Answer:

Work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force

Explanation:

at least part of which is applied in the direction of the displacement. ... To express this concept mathematically, the work W is equal to the force f times the distance d, or W = fd.

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An aircraft travels 1000. km west and then travels 500. km west. what is its total displacement?
UkoKoshka [18]
1000-500=500 km. to the west.
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3 years ago
Unpolarized light with an intensity of 655 W / m2 is incident on a polarizer with an unknown axis. The light then passes through
Norma-Jean [14]

Answer:

1.\theta=29.84^{0}

2.\theta=60.15^{0}

Explanation:

Polarizes axis can create two possible angles with the vertical.

first we have to find the intensity of  first polarizer

which is given as

I=\frac{I_{0} }{2}

I= \frac{655\frac{W}{M^{2} } }{2}

I=327.5\frac{W}{m^{2} }

For a smaller angle for the first polarizer:

According to Malus Law

I_{2} =I_{1} Cos^{2}(90^{0} - \theta)

I_{2} =I_{1} sin^{2}\theta

\frac{I_{2} }{I_{1} }=Sin^{2}\theta

taking square root on both sides

\sqrt{\frac{163}{327.5} } = sin\theta

\theta=Sin^{-1}(0.4977)

\theta=29.84^{0}

For a larger angle for the first polarizer:

According to Malus Law

I_{2} =I_{1} cos^{2}\theta

\frac{I_{2} }{I_{1} }=Cos^{2}\theta

taking square root on both sides

\sqrt{\frac{163}{327.5} } = cos\theta

\theta=Cos^{-1}(0.4977)

\theta=60.15^{0}

7 0
3 years ago
Radiation measured in emissions/sec is called the curie. <br> a. True<br> b. False
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True is the correct anwser


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Which statements about electric field lines are correct? Check all that apply.
slava [35]

Answer:

they cross over one another between charge.

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For B, it is because water is a really good conductor of electricity, so the electrician will get shocked
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