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2 years ago

Define the term work

Physics

2 answers:

weeeeeb [17]2 years ago

6 0

Answer:

Work is the product of force and distance moved in the direction of force.

The Standard International unit is joules.

BY GERALD GREAT

bagirrra123 [75]2 years ago

5 0

Answer:

Work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force

Explanation:

at least part of which is applied in the direction of the displacement. ... To express this concept mathematically, the work W is equal to the force f times the distance d, or W = fd.

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Two conducting spheres are each given a charge Q. The radius of the larger sphere is three times greater than that of the smalle

Vinil7 [7]

Answer:

1/9 of that just outside the smaller sphere

Explanation:

The electric field strength produced by a charged sphere outside the sphere itself is equal to that produced by a single point charge:

$E=k\frac{Q}{r^2}$

where

k is the Coulomb's constant

Q is the charge on the sphere

r is the distance from the centre of the sphere

Calling R the radius of the first sphere, the electric field just outide the surface of the first sphere is

$E_0=k\frac{Q}{R^2}$

The second sphere has a radius which is 3 times that of the smaller sphere:

$R'=3R$

So, the electric field just outside the second sphere is

$E'=k\frac{Q}{R'^2}=k\frac{Q}{(3R)^2}=\frac{1}{9}(k\frac{Q}{R^2})=\frac{E_0}{9}$

So, the correct answer is 1/9.

7 0

2 years ago

The lower the value of the coefficient of friction, the___ the resistance to sliding.

Nuetrik [128]

The lower the value of the coefficient of friction, the lower the resistance to sliding.

<u>Explanation:</u>

The coefficient of friction defines as directly proportionate with the resisting force, which is the frictional force. Hence, if there seems a decrease at coefficient of friction, then it is sure that the frictional force decreases.

We know that the frictional force on a body, is the product of coefficient of frictions and the normal forces acting on the body. Note that friction acts only, if a body is in contact, and it is of three types, static, kinetic and rolling.

4 0

3 years ago

Find the magnitude of the angular momentum of the second hand on a clock about an axis through the center of the clock face. Ass

Naddika [18.5K]

Answer:

L = 4.711 *10^{-6} kg m2/s

Explanation:

$i =\frac{ml^3}{3}$

$= \frac{0.00*.15^2}{3}$

=4.5*10^-5

angular velocity

$\omega = \frac{2\pi}{60}$

= 0.1047 rad/s

the angular momentum,

$L = I\omega$

$L = 4.5*10^{-5}* 0.1047 rad/s$

$L = 4.711 *10^{-6} kg m2/s$

3 0

2 years ago

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It appears as though the moon disappears and the sun comes out in the daytime. Based on what you know, explain why this is happe

zimovet [89]

Answer:

The Earth is toward the sun

Explanation:

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6 0

3 years ago

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A golf ball is released from rest from the top of a very tall building. Choose a coordinate system whose origin is at the starti

Zigmanuir [339]

Answer:

Velocity of the ball after 3.04 (s) = 29.79 (m/s)

Explanation:

From the free fall movement we have the following formulas: $Vf^{2} = Vo^{2} - 2gh$ and $h=Vo*t - \frac{g*t^{2} }{2}$ , First we need to find the height to time iqual to 3.04 s using the formula: $h=Vo*t - \frac{g*t^{2} }{2}$ and remember that golf ball was released from the rest (Vo= 0 (m/s)) so $h= (0 (m/s))*(3.04 (s)) - \frac{9.8 (m/s^2)*(3.04 (s))^{2} }{2}$ , we get: h = -45.28 (m) with the height that we have got, now the velocity of the ball is calculate using $Vf^{2} = Vo^{2} - 2gh$ solving for Vf, we get: $Vf = \sqrt{Vo^{2}-2*g*h }$ replacing the values given $Vf = \sqrt{(0 m/s)^{2}-2*(9.8 m/s^2)*(-45.28 m) }$ , so we get: Vf = 29.79 (m/s).

5 0

3 years ago

Read 2 more answers

Define the term work​

Define the term work