Yes indeed, that is a true statement. Truer words are seldom written, and I could not agree with you more.
In case you are asking a question, I can kind of see how this might be a question if there is a blank after "... the change in ..." that is to be filled with one or more new words.
If that is the situation, then the blank can be filled with "frequency or wavelength" .
Answer:
Δω = -5.4 rad/s
αav = -3.6 rad/s²
Explanation:
<u>Given</u>:
Initial angular velocity = ωi = 2.70 rad/s
Final angular velocity = ωf = -2.70 rad/s (negative sign is
due to the movement in opposite direction)
Change in time period = Δt = 1.50 s
<u>Required</u>:
Change in angular velocity = Δω = ?
Average angular acceleration = αav = ?
<u>Solution</u>:
<u>Angular velocity (Δω):</u>
Δω = ωf - ωi
Δω = -2.70 - 2.70
Δω = -5.4 rad/s.
<u> Average angular acceleration (αav):</u>
αav = Δω/Δt
αav = -5.4/1.50
αav = -3.6 rad/s²
Since, the angular velocity is decreasing from 2.70 rad/s (in counter clockwise direction) to rest and then to -2.70 rad/s (in clockwise direction) so, the change in angular velocity is negative.
Answer:
Rockets provide a wonderful example of Momentum Conservation. As momentum in one direction is given to the rocket's exhaust gases, momentum in the other direction is given to the rocket itself.
Explanation:
First, think of two masses connected by a lightweight (massless!) compressed spring. When the two spring apart, conservation of momentum tells us the Center of Mass remains where it was (or moving as it was).
PTot,i = p1i + p2i = 0 + 0 = 0
PTot,f = p1f + p2f = PTot,i = 0
p1f + p2f = - m1 v1f + m2 v2f = 0
Answer:
615 N
Explanation:
If θ is the angle from vertical and T is the rope tension
θ = arcsin (2.0 / 3.5) = 34.85°
Summing vertical forces to zero
Tcosθ - mg = 0
T = 90.0(9.81) / cos34.85 = 1,075.85 N
Summing horizontal forces to zero
F - Tsinθ = 0
F = 1075.85sin34.85 = 1075.85(2.0/3.5) = 614.772... ≈ 615 N
Answer:
The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight is approximately 19.81 m/s
Explanation:
The given parameters are;
The curvature of the hill, r = 200 m
Due to the velocity, v, the occupants weight = 20% less than the normal weight
The outward force of an object due to centripetal (motion) force is given by the following equation;
Where;
r = The radius of curvature of the hill = 200 m
Given that the weight of the occupants, W = m × g, we have;
v = √(0.2 × g × r)
By substitution, we have;
v = √(0.2 × 9.81 × 200) ≈ 19.81
The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight ≈ 19.81 m/s.
