The minimum stopping distance when the car is moving at 32.0 m/s is 348.3 m.
<h3>
Acceleration of the car </h3>
The acceleration of the car before stopping at the given distance is calculated as follows;
v² = u² + 2as
when the car stops, v = 0
0 = u² + 2as
0 = 15² + 2(76.5)a
0 = 225 + 153a
-a = 225/153
a = - 1.47 m/s²
<h3>Distance traveled when the speed is 32 m/s</h3>
If the same force is applied, then acceleration is constant.
v² = u² + 2as
0 = 32² + 2(-1.47)s
2.94s = 1024
s = 348.3 m
Learn more about distance here: brainly.com/question/4931057
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No, he did not perform any work. Work is when you’re using energy which results in a force. Even though he was tired and sweaty, he did not move the boulder. So therefore he did not perform any work.
Answer:
B) protons and neutrons
Explanation:
An atom has a nucleus made of protons and neutrons, and electrons surrounding the nucleus
I'm such a devoted NASCAR fan that I don't even know if the starting line and finish line at Indy are the same line ... or maybe they're in different places, like the 100-meter sprint in track.
I have no idea, but I'm going to guess that the start and finish at Indy are the SAME line.
If that's true, then the displacement of a car that runs the whole 500 miles is very close to <em>ZERO</em>.
Displacement is the distance and direction between the place where the object starts out and the place where it ends up. The route it follows to get from the start to the finish is completely ignored, and doesn't matter.
(Do they the Indianapolis 500 in "stock" cars ? ?)
