Question

The animal rescue has 3 cats for

Answer 1

Let cats be x

• Dogs be x+20

ATQ

$\\ \sf\longmapsto \dfrac{x}{x+20}=\dfrac{3}{8}$

$\\ \sf\longmapsto 8x=3(x+20)$

$\\ \sf\longmapsto 8x=3x+60$

$\\ \sf\longmapsto 8x-3x=60$

$\\ \sf\longmapsto 5x=60$

$\\ \sf\longmapsto x=\dfrac{60}{5}$

$\\ \sf\longmapsto x=12$

$\\ \sf\longmapsto x+20=12+20=32$

Answer 2

Answer:

32

Step-by-step explanation:

8-3=5

20÷5=4 sets

Hence, no. of dogs=4×8

=32