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3 years ago

If an object is accelerating at 4 m/s^2 and has a mass of 8 kg, what is the net

Physics

2 answers:

Salsk061 [2.6K]3 years ago

7 0

Answer:

The force applied is 32 N

Explanation:

F = ma

F = 8 × 4

F = 32 N

cricket20 [7]3 years ago

4 0

Answer:

$\boxed {\boxed {\sf 32 \ Newtons}}$

Explanation:

We are asked to find the net force on an object. According to Newton's Second Law of Motion, force is the product of mass and acceleration. Therefore, the formula for calculating force is:

$F= m \times a$

The mass of the object is 8 kilograms and its acceleration is 4 meters per second squared.

m= 8 kg
a= 4 m/s²

Substitute these values into the formula.

$F= 8 \ kg \times 4 \ m/s^2$

Multiply.

$F= 32 \ kg *m/s^2$

Convert the units. 1 kilogram meter per second squared is equal to 1 Newton. So, our answer of 32 kilogram meters per second squared is equal to 32 Newtons.

$F= 32 \ N$

The net force on the object is <u>32 Newtons.</u>

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2 years ago

Read 2 more answers

A ball is droped from a height of 16m how much time will pass before the ball hits the ground

sergey [27]

Answer:

The time is 1.8s

Explanation:

The ball droped, will freely fall under gravity.

Hence we use free fall formula to calculate the time by the ball to hit the ground

$h= \frac{1}{2}g{t}^{2}$

Where h is the height from which the ball is droped, g is the acceleration due to gravity that acted on the ball, and t is the time taken by the ball to hit the ground.

From the question,

h=16m

Also, let take

$g = 9.8m{s}^{-2}$

By substitution we obtain,

$16= \frac{1}{2}\times 9.8{t}^{2}$

$\implies32=9.8{t}^{2}$

Diving through by 9.8

$\frac{32}{9.8}= \frac{ 9.8{t}^{2} }{9.8}$

$\implies{t}^{2} =3.265$

square root both sides, we obtain

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A person of mass m is standing on the surface of the Earth, of mass M E . What is the acceleration that the Earth experiences du

Lana71 [14]

Answer:

$a_E=\dfrac{Gm}{r^2}$

Explanation:

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