Question

When wile coyote is launched his velocity is 20 m/s. As a slightly underweight 10kg coyote, how far would the 400 N/m spring have been stretched to give him this speed?

Answer 1

Answer:

E = 1/2 m v^2 = 1/2 k x^2     equating KE of coyote and spring

x^2 = m v^2 / k = 10 kg * 20^2 m^2 / s^2 / 400 N / m

x^2 = 10 * 400 / 400 (kg m^3 / kg-m) = 10 m^2

x = 3.16 m