Answer:
<em>The correct option is a) Precipitate: silver sulfate
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<em>Net Ionic: 2Ag+ + SO42 →Ag2SO4</em>
Explanation:
When sodium sulfate reacts with silver nitrate, the following reaction occurs:
2AgNO3 + Na2SO4 → Ag2SO4 + 2NaNO3
The NaNO3 is easily soluble in water. However, silver ions form an insoluble solid with SO4. The Ag+ in this compound will be a cation having a positive charge. The SO4- will be an anion having an negative charge.
The table with solubility rules show that the sulfates of Ag+, Ca+, Sr2+, Ba2+, Hg22+ and Pb2+ are insoluble.
1Al2(SO4)3 + 3ZnCl2 → 2AlCl3 + 3ZnSO4
The coefficients represents moles. There is 1 mole of Aluminum Sulfate, 3 moles of Zinc(II) Chloride, 2 moles of Aluminum Chloride, and 3 moles of Zinc(II) Sulfate.
Now add all the coefficients/moles.
9 is the sum of all the coefficients.
The subscript 3 outside of the parentheses means to multiply everything in the parentheses by 3, so it becomes a matter of addition:
3*(CH3) * (1 carbon atom)/(CH3) = 3 carbon atoms in (CH3)3
CH has one carbon atom and one hydrogen atom, so:
1 carbon atom in CH
Add both of them together, and you get 4 carbon atoms in isobutane
The outer layers are the photosphere the chromosphere the transition region in the corona
Answer: It's the anode broski (B)
Explanation: I'm taking the Chem summer course too broski, this was the correct answer. Cheers broski
