Find the 
from 
The 
value of 
is
The value finally becomes,
<h3>
What are the properties of Saturated solution ?</h3>
A saturated solution is one that contains all of the solute that can possibly dissolve in it. The most sodium chloride that may dissolve in 
of water at 
°C is 
. Past that point, adding more 
won't cause it to dissolve because the solution is already saturated.
The solution reaches a point when it is saturated. This indicates that if you add more of the substance, it will stop dissolving and instead stay solid. The amount depends on how the solvent and solute interact molecularly.
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Answer:
Vapor pressure of solution = 23.9 Torr
Explanation:
Let's apply the colligative poperty of vapor pressure to solve this:
ΔP = P° . Xm
ΔP = Vapor pressure of pure solvent - Vapor pressure of solution
We have solvent and solute mass, so let's find out the moles of each.
55.3 g / 62 g/mol = 0.89 moles
285.2 g / 18 g/mol = 15.84 moles
Let's determine the mole fraction of ethylene glycol.
Mole fraction = Moles of ethylene glyco / Total moles
0.89 moles / (0.89 + 15.84) = 0.053
25.3 Torr - Vapor pressure of solution = 25.3 Torr . 0.053
Vapor pressure of solution = 25.3 Torr . 0.053 - 25.3 Torr
Vapor pressure of solution = 23.9 Torr
Ice, freezing, or melting then liquid evaporation or condensation, the vapor, deposition the ice again
2C3H6 (g) + 2NH3 (g) + 3O2 (G) -> 2C3H3N (g) + 6H2O (g)
First off.. not a chem board.. but n e way.
This is a limiting reagent problem.
set it up as a DA problem.(Dimension Analysis)
Start with what you want.
you want Grams of acrylonitrile (C3H3N)
so start with that (Using ACL in place of Acrylonitrile.. just for ease of typing)
(g) = (53 g of ACL/1mol ACL) (2 mols ACL/2 mol C3H6)/ (1mol C3H6/42 grams) (15.0 grams)
solve that you wiill get grams of Acrylonitrile created by 15 grams oc C3H6 = 18.9g
Same setup for the two other reactants.
so i did it and for
oxygen I got 11.04 grams
and for Ammonia i got 15.29 grams
So the most you can make is 11.04 grams because if you have ot make any more .. you will have to get more O2 .. but since you have only 10 grams of it .. that is the most u can make in this reaction.
Both the other reactants are in excess.
rate brainliest pls
Particle, Relative Mass<span>, Actual </span>Mass<span> (g) </span>Electron<span>- 1 , 9.11*10 power -28 g. ... Calculate: What is the diff </span>expressed in kg between the mass<span> of a </span>proton and the mass<span> ... Best Answer: </span>difference<span>in </span>mass<span> = [1.673 x 10^(-24) - 9.11 x ...</span>
