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nataly862011 [7]
3 years ago
8

Plz answer it..pzzzz​

Physics
2 answers:
dolphi86 [110]3 years ago
7 0

Answer:

I think it's current.

It cannot be Temperament because temp's S.I unit is Kelvins

Alecsey [184]3 years ago
3 0

Answer:

I think the answer is tempurature

Explanation:

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What is the kinetic energy of a vehicle that has a mass of 3,500 kg and is moving at 40 m/s
stiv31 [10]

Answer:2800000j

Explanation:

For us to know the kinetic energy of the vehicle,

Where m is the mass

And v is the velocity

Then, K.E=1/2mv^2

While, K.E=1/2×3500×40^2

Therefore, our answer will now be

K.E=2800000j

5 0
3 years ago
A ball of mass 0.10 kg moving at a speed of 3.0 m/s collides with a wall and bounces directly back with the same speed. If the b
alexdok [17]

The magnitude of the average force exerted on the ball by the wall is calculated below.

The average force exerted by the ball on the wall is 3 N

Explanation:

Given:

mass of the ball (m)=0.10 kg

speed (v) =3.0 m/s

time taken(t) =0.01 seconds

To calculate:

Average force(F) exerted by ball on the wall

We know;

F=(m×v)÷t

F=(0.10×3.0)÷0.01

<u><em>F=3 N</em></u>

Therefore the average force exerted by the ball on the wall is 3 N

8 0
4 years ago
The gravitational force between two objects is proportional to the square of the distance between the two objects.
Darina [25.2K]

Answer: True!

Explanation: The force is proportional to the square of the distance between 2 point masses

3 0
3 years ago
At t = 0 the components of a radio-controlled car's velocity are vx = 0.5 m/s and vy = 1.2 m/s. Find the components of the car's
FinnZ [79.3K]

Answer:

x-component of velocity = 5.7 m/s

y-component of velocity = -1.4 m/s          

Explanation:

Use first equation of motion to find components of velocity at a given time:

v = u + at

where, v is  the final velocity, u is the initial velocity, a is the acceleration and t is the time.

Given:

u_x= 0.5 m/s\\u_y=1.2 m/s\\a_x=2 m/s^2\\a_y=-1m/s^2\\t = (2.6-0)s =2.6 s

v_x=u_x+a_xt\\\Rightarrow v_x=0.5+2\times 2.6\\\Rightarrow v_x=5.7 m/s

v_y=u_y+a_yt\\\Rightarrow v_y=1.2-1\times 2.6\\\Rightarrow v_y=-1.4 m/s

5 0
3 years ago
A 1,250 kg car is moving due to 6,500 N engine force. If the kinetic friction coefficient between the car and the road is 0.32,
Yuliya22 [10]

Answer:

b i hope this is correct answee

7 0
3 years ago
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