V=IR
Potential Difference (v)= Current (A) * Resistance (Ω)
As V increases, R also increases.
Answer:
a. 2.1 s
b.0.48 Hz
c. A=24cm
d. 72cm/s
Explanation:
An air-track glider attached to a spring oscillates between the 10.0 cm mark and the 57.0 cm mark on the track. The glider completes 15.0 oscillations in 31.0 s.What are the (a) period, (b) frequency, (c) amplitude, and (d) maximum speed of the glider?
What are the period,
period is the time taken for a wave particle to make one complete oscillation
a) 31 / 15 = 2.066 seconds
= 2.1 s
(b) frequency
: this the number of oscillation made in one seconds.
it is also the inverse of the period.
= oscillations / time
= 15/31= 0.48 Hz
(c) amplitude
: maximum displacement from the origin
amplitude = 1/2 of the difference of oscillation marks
= 1/2(57-10) = 47/2cm
23.5cm
A=24cm
(d) maximum speed of the glider?
V=ωA
angular frequency *Amplitude
V=a*pi*f*amplitude
2π x frequency x amplitude = maximum speed
= 2π x .48 x 24
=72.38 cm/s
72cm/s
Efficiency of heat engine is determined by the ratio of difference in temperature of cold from hot reservoir to the temperature of hot reservoir over temperature of hot reservoir.
Answer: Option A
<u>Explanation:</u>
Efficiency is defined as the output from the input. So it is the ratio of energy output to the energy input. In case of temperature, it is the change in temperature from hot reservoir to cold reservoir with the overall hot reservoir temperature.
Thus, option A is the most suitable as the heat will be transferred from high temperature to low temperature. So the hot reservoir will be releasing the energy. So the conversion of hot reservoir temperature to cool reservoir temperature is defined as the efficiency. Thus, option A is the most suitable.
Answer:
Explanation:
I was unable to submit this answer after typing it, so i create a document file that clearly shows and depicts all explanations for the question. OR
You can check the three picture slides i attached as well for the explanation.
The attached file for the document and the picture can be found below.
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark">
docx
</span>
Answer:
5.03 m/s
Explanation:
Give
Speed = v = 24m/s
Wavelength = λ = 30cm = 0.3m
Amplitude = A = 1.0cm = 0.01m
The velocity of a point in Simple Harmonic Motion
at any time t is given by the following formula
v = ωA cos ωt
The value is the Maximum when cosωt.
The maximum value of cosωt. is 1.
Hence the maximum velocity is ωA
Velocity of the wave v=n λ
n = v/ λ = 24 /0.3 = 80
ω = 2πn = 2π*80 = 502.86 rad/s
Maximum velocity of the particle is
ωA = 502.86 * 0.01 = 5.03m/s
