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stiv31 [10]
3 years ago
8

Convert 22000mg to cg

Physics
1 answer:
Art [367]3 years ago
7 0

Your answer is.. 22000 mg = 2200 cg

Because:

1 mg = 0.1 cg

I hope this helps!

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In two or more complete sentences, explain the effect of gases being trapped in the atmosphere.
MAVERICK [17]
Earth's surface warms up in the sunlight. At night, Earth's surface cools, releasing the heat back into the air. But some of the heat istrapped<span> by the greenhouse </span>gases<span> in the </span>atmosphere<span>. ... Greenhouse </span>effect<span> of Earth's </span>atmosphere<span> keeps some of the Sun's energy from escaping back into space at night.</span>
8 0
4 years ago
What average net force is required to accelerate a 9.5 g
Nesterboy [21]

Answer:

2361 Newtons

Explanation:

From the second Newton's law of motion;

F = ma

In this case;

we are given;

Mass as 9.5 g

Initial speed as 0 m/s

Final velocity as 650 m/s

Distance is 0.85 m

Using the equation;

V² = U² + 2as

But u = 0

v² = 2as

Therefore;

a = v² ÷ 2s

  = 650² ÷ 2(0.85)

  = 248,529.40 m/s²

But;

F = ma

   = 0.0095 kg × 248,529.40 m/s²

   = 2361 Newtons

Therefore;

The average net force required to accelerate the bullet is 2361 Newtons.

6 0
3 years ago
An organ pipe open at both ends has a radius of 4.0 cm and a length of 6.0 m. what is the frequency (in hz) of the third harmoni
Marysya12 [62]

When air is blown into the open pipe,

L = \frac{nλ}{2}

where nis any integral number 1,2,3,4 etc. and λ is the wavelength of the oscillation

⇒λ=\frac{2L} {n}

Note here that n=1 is for fundamental, n=2 is first harmonic and so on..

⇒ third harmonic will be n=4

Given L=6m, n=4, solving for λ we get:

λ=\frac{(2)*(6)}{4} =3m

Relationship of frequency(f), velocity of sound (c) and wavelength(λ) is:

c=f.λ Or f= \frac{c}{λ}

⇒f=\frac{344}{3}

≈115 Hz

8 0
4 years ago
The kinetic friction coefficient between a cabinet and the floor is 0.3. Mass of the cabinet is 300kg. A man pushes the cabinet
podryga [215]

Answer:

<h2>0.39m/s^2</h2>

Explanation:

Step one:

given data

mass m= 300kg

applied force F= 1000N

coefficient of friction μ= 0.3

Step two:

The net force Fn= applied force-friction force  

Fn=F-F1

F1= limiting force

F1=μ*m*g

F1=0.3*300*9.81

F1=882.9N

the Net force= 1000-882.9

Fn=117.1N

Step three:

we know that

F=ma

Fnet=ma

a= Fnet/m

a=117.1/300

a=0.39m/s^2

7 0
3 years ago
Calculate the solubility (in m units) of ammonia gas in water at 298 k and a partial pressure of 2.50 bar . the henry's law cons
Eduardwww [97]
Henry's Law (formulated in 1803 by William Henry) states that aa constant temperature, the amount of gas dissolved in a liquid is directly proportional to the partial pressure exerted by that gas on the liquid.
 Mathematically it can be formulated as
 C = H⨯P
 being:
 C: the molar concentration of dissolved gas A,
 P: the partial pressure of it
 H: Henry's constant
 Substituting:
 C = P * H
 C = (2.50 * 0.9869) * 58.0
 C = 143.1
 Answer:
 the solubility (in m units) is
 C = 143.1
8 0
3 years ago
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