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hammer [34]
3 years ago
15

How is clayey soil useful for crops?

Chemistry
1 answer:
joja [24]3 years ago
7 0

Answer:

Clayey soil is rich in humus and very fertile, so it is suitable for growing cereals like wheat and gram. Such soil is good at retaining water.Clayey is known to be useful for crops. Because the particle size in this soil is very fine, it has the ability to retain more amounts of water. - This makes it easy for crops to access water as it is very essential for the growth of the plant. - Some of the crops need a high amount of water in order to grow.Clayey soil is made up of fine particles that are tightly packed and increases soil density and strength. It is rich in nutrient content in the form of organic matter or humus so, it is very fertile soil. It has excellent water retaining a capacity.

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Calculate the electric double layer thickness of a alumina colloid in a dilute (0.1 mol/dm3) CsCI electrolyte solution at 30 °C.
Ad libitum [116K]

Explanation:

The given data is as follows.

    Concentration = 0.1 mol/dm^{3}

                             = 0.1 \frac{mol dm^{3}}{dm^{3}} \frac{10^{3}}{dm^{3}} \times \frac{6.022 \times 10^{23}}{1 mol} ions

                             = 6.022 \times 10^{25} ions/m^{3}

               T = 30^{o}C = (30 + 273) K = 303 K

Formula for electric double layer thickness (\lambda_{D}) is as follows.

            \lambda_{D} = \frac{1}{k} = \sqrt \frac{\varepsilon \varepsilon_{o} K_{g}T}{2 n^{o} z^{2} \varepsilon^{2}}

where, n^{o} = concentration = 6.022 \times 10^{25} ions/m^{3}

Hence, putting the given values into the above equation as follows.

                 \lambda_{D} = \sqrt \frac{\varepsilon \varepsilon_{o} K_{g}T}{2 n^{o} z^{2} \varepsilon^{2}}                    

                          = \sqrt \frac{78 \times 8.854 \times 10^{-12} c^{2}/Jm \times 1.38 \times 10^{-23}J/K \times 303 K}{2 \times 6.022 \times 10^{25} ions/m^{3} \times (1)^{2} \times (1.6 \times 10^{-19}C)^{2}}  

                         = 9.669 \times 10^{-10} m

or,                     = 9.7 A^{o}

                          = 1 nm (approx)

Also, it is known that \lambda_{D} = \sqrt \frac{1}{n^{o}}

Hence, we can conclude that addition of 0.1 mol/dm^{3} of KCl in 0.1 mol/dm^{3} of NaBr "\lambda_{D}" will decrease but not significantly.

7 0
3 years ago
what mass of carbon dioxide will be produced when 12.9 g of butane reacts with an excess of oxygen in the following reaction?
Nadya [2.5K]
39.1 gCO2
I think if that’s an option
3 0
3 years ago
Due in minutes! Please Help Solve!
stiks02 [169]
Step by step equation
5 0
3 years ago
W
DerKrebs [107]

Answer:

F = 30 N

Explanation:

Given data:

Mass of toy train = 1.5 kg

Acceleration of train = 20 m/s²

Amount of force acting on it = ?

Solution:

The net force on object is equal to the its mass multiply by its acceleration.

Formula:

F = ma

F = force

m = mass

a = acceleration

Now we will put the values in formula.

F = 1.5 kg × 20ms⁻²

F = 30 kg.ms⁻²

kg.ms⁻² = N

F = 30 N

7 0
3 years ago
According to the kinetic-molecular theory, the average kinetic energy of gas
vladimir1956 [14]

Answer:

The average kinetic energy of a gas depends only on its temperature.

Explanation:

The average kinetic energy of particles in a gas can be found using the equation

\displaystyle \text{Average K.E.} = \frac{3}{2}k\cdot T,

where

  • k is the Stefan-Boltzmann constant, and
  • T is the absolute temperature of this gas (the one in degree Kelvins.)

As seen in this equation, the average kinetic energy of particles in a gas depends only on the temperature of the gas. Also, since the question is asking for the average not the total kinetic energy, the number of particles in this gas doesn't matter, either.

8 0
3 years ago
Read 2 more answers
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