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emmainna [20.7K]
2 years ago
12

A 5.6 g marble is fired vertically upward using a spring gun. The spring must be compressed 6.4 cm if the marble is to just reac

h a target 15 m above the marble's position on the compressed spring. What is the change in the gravitational potential energy of the marble-Earth system during the 15 m ascent
Physics
1 answer:
N76 [4]2 years ago
5 0

Answer: im not gonna give i to you just do 15+15=_+ 5.6+6.4 easy

Explanation: i took the test and got a 100%

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12 V is the f.e.m. \epsilon of the battery. The potential difference that is applied to the motor is actually the fem minus the voltage drop on the internal resistance r:
\epsilon - Ir
this is equal to the voltage drop on the resistance of the motor R:
RI
so we can write:
\epsilon - Ir = RI
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If you double the distance between you and the center of Earth, what happens to the strength of the gravitational field you expe
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7 0
3 years ago
A piano tuner sounds two strings simultaneously. One has been previously tuned to vibrate at 293.0 Hz. The tuner hears 3.0 beats
ololo11 [35]

Answer:

Part a)

f_B = 290 Hz

Part B)

percentage increase is

percentage = 1.38%

Explanation:

Part a)

As we know that the beat frequency is

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after increasing the tension the beat frequency is decreased and hence the tension in string B will increase

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Part B)

percentage increase in the tension of the string will be given as

f_A - f_B' = 1

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now we have

f = \frac{1}{2L}\sqrt{\frac{T}{\mu}}

so we have

T_1 = C (290)^2

T_2 = C(292)^2

so we have

\frac{\Delta T}{T} = \frac{292^2 - 290^2}{290^2}

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4 0
4 years ago
while spinning in a centrifuge a 70.0 kg astronaut experiences an acceleration of 5.00 g, or five times the acceleration due to
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Answer:

Explanation:

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