Answer:
Upper cuticle and guard cells
A catalyst is a substance that speeds up the rate of a chemical reaction but is not consumed during the course of the reaction.
A catalyst will appear in the steps of a reaction mechanism,but it will not appear in the overall chemechal reaction
i hoped this helped
by the way can you mark me the brainliest
.since i was the only one to answer youre question
;P thanks bye
First, convert 2.0 mL of AlCl3 to grams using the density, which is 2.48g/mL. So 2.48g/mL * 2.0 mL = 4.96g. Then find the molar mass of aluminum chloride and divide 4.96 by this number, which is 133.34g. 4.96g*(1mol/133.34g) = .0372 mols AlCl3. Check for significant digits though.
Answer: It's the first one :3
Explanation:
Molarity of acid=2.5M
pH=5.1.
ka=?
Now
We need to write an eqn to show the dissociation of the acid
HA + H2O === H3O+ + A-
Writing The Equilibrium(Or Acid dissociation constant) of this reaction
Ka =[H3O+] {A-]/ {HA].
The concept behind this is
concentration of Products divided by those of reactants. Water is not written because its a pure liquid and does not affect the Equilibrium constant.
Now If you have any Idea on ICE tables..
You'd know that the concentration of acid will decrease by 2.5-x
Whilst the products...will increase by x each
Note: This is when the ratio of their Moles are in 1:1
ka= x.x/2.5-x
Since the Moles of A- and H3O+ are in 1:1... Their concentrations at equilibrium will be the same
so
Ka= x²/2.5-x
Now what is x??
x is the Hydrozonium ion concentration.
we can get it from the pH formula
pH= -log (H3O+)
Making H3O+ subject by applying Logarithm Rules
H3O+ = 10^-ph
x=10^-5.1
=7.94x10^-6.
Now back to Ka
Ka= x²/2.5-x
Ka= (7.94x10^-6)²/2.5-(7.94x10^-6)
Ka= (7.94x10^-6)²/2.4999
Ka= 2.52x10^-11.
Was a Fun One