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steposvetlana [31]
3 years ago
8

What is role of iron in chemical reaction?

Chemistry
2 answers:
Serggg [28]3 years ago
4 0

Answer:

<h2>4 heat </h2>

Explanation:

<h2>plz mark me as brain list </h2>
mojhsa [17]3 years ago
3 0

Answer:

4.....

Explanation:

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The chemistry lab is 0.3394km from the nurses office. How many feet is the distance?
nlexa [21]
Easy just convert it to feet the answer is <span>1113.51706 Feet

</span>
6 0
4 years ago
Determine what is missing from this neutralization reaction: AgNO3+KCl→AgCl+−−−−
lapo4ka [179]

Answer:

The answer to your question is: KNO₃

Explanation:

                                AgNO3  +  KCl   →   AgCl  +   −−−−

A. KNO3    this option is correct because it is a double replacement reaction then potassium must attached to NO₃.

B. KOH  this product is not possible because there is no water to form OH⁻ ions.

C. Ag2K  this product is not possible because both Ag and K are metals, then it is difficult that they attach.

D. KN2O This product is imposible to form, this option is wrong.

7 0
3 years ago
Calcium phosphate consists of two ions chemically bonded together. What are charges of each ion?
sdas [7]

Answer: Ca^2+ and P^3-

Explanation:

7 0
3 years ago
In a synthesis reaction, one reactant contains 346 J of chemical energy, and one reactant contains 153 J of chemical energy. The
Eduardwww [97]

Answer:

64J of energy must have been released.

Explanation:

Step 1: Data given

One reactant contains 346 J of chemical energy, the other reactant contains 153 J of chemical energy.

The product contains 435 J of chemical energy.

Step 2:

Since the energy is conserved

Sum of energy of Reactants = Energy of Products

Sum of energy of Reactants = 346 J + 153 J = 499 J

The energy of the product = 435 J

435 < 499

This means energy must have been lost as heat.

Step 3: Calculate heat released

499 J - 435 J = 64 J

64J of energy must have been released.

4 0
3 years ago
Cyclopropene decomposes to propene when heated to 500 C, calculate rate constant for the first order reaction 0 min 1.48 mmol/L
Dmitry_Shevchenko [17]

Answer:

k = 0.0306 min-1

Explanation:

The table is given as;

Time, Concentration

0 1.48

5 1.27

10 0.98

15 0.84

The integrated rate law for a first order reaction is given as;

ln [A] = -kt + ln [Ao]

where;

[A] = Final Concentration

[Ao] = Initial Concentration

k = rate constant

t = time

In the table, taking the first two sets of values;

t = 5

k = ?

[Ao]  = 1.48

[A] = 1.27

Inserting into the equation;

ln(1.27) = - k (5) + ln(1.48)

ln(1.27)  - ln(1.48) = -5k

-0.1530 = -5k

k = -0.1530 / -5

k = 0.0306 min-1

6 0
3 years ago
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