B.) acceleration.
hope this helps:)
<span>8•5. Lesson 6. Lesson 6: Graphs of Linear Functions and Rate of Change ... in the table below: Input Output. 2. 5. 3.5. 8. 4. 9. 4.5. 10. ▫. The graph of a linear ... Yes, the rate of change betweeneach pair of inputs and outputs does seem to be .... The graph of the function will be a plot of fourpoints lying on a common line.</span><span>
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Answer: Option (b) is the correct answer.
Explanation:
As on increasing the temperature, the molecules gain more kinetic energy due to which they tend to collide and move rapidly from one place to another.
Thus, we can conclude that when temperature is increased, the kinetic energy of the molecules increases. This means that temperature is directly proportional to the average kinetic energy of a gas.
Answer:
The force is 
Explanation:
From the question we are told that
The first diameter is 
The second diameter is 
Generally the first area is

=> 
=> 
The second area is



For a hydraulic press the pressure at both end must be equal .
Generally pressure is mathematically represented as

=>

=> 
=> 
Answer:
The observed frequency by the pedestrian is 424 Hz.
Explanation:
Given;
frequency of the source, Fs = 400 Hz
speed of the car as it approaches the stationary observer, Vs = 20 m/s
Based on Doppler effect, as the car the approaches the stationary observer, the observed frequency will be higher than the transmitted (source) frequency because of decrease in distance between the car and the observer.
The observed frequency is calculated as;
![F_s = F_o [\frac{v}{v_s + v} ] \\\\](https://tex.z-dn.net/?f=F_s%20%3D%20F_o%20%5B%5Cfrac%7Bv%7D%7Bv_s%20%2B%20v%7D%20%5D%20%5C%5C%5C%5C)
where;
F₀ is the observed frequency
v is the speed of sound in air = 340 m/s
![F_s = F_o [\frac{v}{v_s + v} ] \\\\400 = F_o [\frac{340}{20 + 340} ] \\\\400 = F_o (0.9444) \\\\F_o = \frac{400}{0.9444} \\\\F_o = 423.55 \ Hz \\](https://tex.z-dn.net/?f=F_s%20%3D%20F_o%20%5B%5Cfrac%7Bv%7D%7Bv_s%20%2B%20v%7D%20%5D%20%5C%5C%5C%5C400%20%3D%20F_o%20%5B%5Cfrac%7B340%7D%7B20%20%2B%20340%7D%20%5D%20%5C%5C%5C%5C400%20%3D%20F_o%20%280.9444%29%20%5C%5C%5C%5CF_o%20%3D%20%5Cfrac%7B400%7D%7B0.9444%7D%20%5C%5C%5C%5CF_o%20%3D%20423.55%20%5C%20Hz%20%5C%5C)
F₀ ≅ 424 Hz.
Therefore, the observed frequency by the pedestrian is 424 Hz.