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luda_lava [24]
2 years ago
14

Asap plz Which statement describes a controlled experiment?

Physics
1 answer:
miss Akunina [59]2 years ago
6 0

Answer:

B, it includes a control group and an experimental group.

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A 48 kg cart is sitting motionless at the top of the hill. At what height, did the cart start at, to reach 88435 J of energy at
svet-max [94.6K]

Answer : The height is 188 meters  

Explanation :   When the cart reached at the end from top of hill then the cart have potential energy .

Given that,

Potential energy = 88435 J

Mass of cart = 48 kg

We know that,

The potential energy is

mgh =88435

h= \dfrac{88435}{48\times9.8}

h = 187.9 = 188\ meters

So, the height of the top is 188 meters.

7 0
4 years ago
If you used 16 gallons when driving 367 miles, what was your gas mileage over that distance
White raven [17]
Your gas mileage would be 22.93 miles per gallon.
6 0
3 years ago
What is the wavelength of a 2.50-kilohertz sound
Alexxx [7]
The formula v=fλ can be used here.

326=2500*λ

Note the 2500 as 2.5kHz is 2.5 thousand Hz.

λ = 326/2500
= 0.1304m = 0.130m
3 0
3 years ago
a rocket with a mass of 4kg accelerates up from the ground at a rate of 20ft m/s^2, what is the drag force acting on the rocket
Maru [420]

The drag force acting on the rocket is 80N.

<h3>Give an explanation of drag force?</h3>

The divergence in velocity between the fluid and the item, also known as drag, exerts a force on it. Between the liquid and the solid object, there should be motion. Drag is absent in the absence of motion.

The air molecules are more compressed (pushed together) on the surfaces that are facing the front while being more dispersed (spread out) on the surfaces facing the back. Turbulent flow, which occurs when air layers split from the surface and start to swirl, is what causes this.

The drag force acting on the rocket F = ma

Given,

m = 4kg, a = 20ftm/s²

Substituting m and a values in the above formula,

The drag force acting on the rocket F = 4×20

The drag force acting on the rocket F = 80N.

To know more about drag force visit:

brainly.com/question/15144984

#SPJ4

8 0
1 year ago
Calculate the magnitude of electric field strength at a point 3cm from an infinite line of charge of linear density 18 μC/cm sit
valina [46]
Answer:

The magnitude of the electric field strength = 7.2 x 10⁸ N/C

Explanation:

The linear density:

\begin{gathered} \lambda=18\mu C\text{ /cm} \\  \\ \lambda=\frac{18*10^{-6}C}{0.01m} \\  \\ \lambda=0.0018\text{ C/m} \end{gathered}

Point r = 3 cm = 3/100 m

r = 0.03 m

The electric field strength is calculated below

\begin{gathered} E=\frac{\lambda}{2\pi\epsilon_o\epsilon_rr} \\  \\ E=\frac{0.0018}{2\times3.14\times8.85\times10^{-12}\times1.5\times0.03} \\  \\ E=719709237.468\text{ N/C} \\  \\ E=7.2\times10^8\text{ N/C} \\  \end{gathered}

The magnitude of the electric field strength = 7.2 x 10⁸ N/C

8 0
1 year ago
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