First,
where 
is density, 
is mass, and 
is volume. We can compute the volume of the roll:
When the roll is unfurled, the aluminum will be a rectangular box (a very thin one), so its volume will be the product of the given area and its thickness 
. Note that we're assuming the given area is not the actual total surface area of the aluminum box, but just the area of the largest face (i.e. the area of one side of the unrolled sheet of aluminum).
So we have
where 
is the given area, so
If we're taking significant digits into account, the volume we found would have been 
, in turn making the thickness 
.
The height of the liquid column is 4.08 metres.
Answer:
B) The lightbulb uses 4,104,000 J more than the stereo.
RT = R1 R2/ R1 + R2
R1 = R2 = 2k ohm
RT = R/2 = 2k/2 = 1k ohm
Answer:
Divide then multiply or multiply then divide
Explanation:
to get the answer of a and b
