Answer:
C = 0.08M
Explanation:
molar mass of AlCl3
Al =27
Cl = 35.5
27+3(35.5) =133.5g/mol
n= mass/Molar mass
n =CV
CV = mass/molar mass
C x 500 x 10^-³ = 5/133.5
C x 500 x 10^-³ = 0.04
C = 0.04/500 x 10^-³
C = 0.08M
Substitution Reactions are those reactions in which one nucleophile replaces another nucleophile present on a substrate. These reactions can take place via two different mechanism i.e SN¹ or SN². In SN¹ substitution reactions the leaving group leaves first forming a carbocation and nucleophile attacks carbocation in the second step. While in SN² reactions the addition of Nucleophile and leaving of leaving group take place simultaneously.
Example:
OH⁻ + CH₃-Br → CH₃-OH + Br⁻
In above reaction,
OH⁻ = Incoming Nucleophile
CH₃-Br = Substrate
CH₃-OH = Product
Br⁻ = Leaving group
Organic reactions are typically slower than ionic reactions because in organic compounds the covalent bonds are first broken, this breaking of bonds is a slower step, while, in ionic compounds no bond breakage is required as it consists of ions, so only bond formation takes place which is a quicker and fast step.
Answer:
2257000 J
Explanation:
Applying,
Q = Cₓm.................. Equation 1
Where Q = amount of energy need to boil the water, Cₓ = Enthalpy of vaporization of water, m = mass of water.
From the question,
Given: Cₓ = 2257000 J/kg, m = 1 kg
Substitute these values into equation 1
Q = 2257000×1
Q = 2257000 J
Hence the energy needed to boil all of the water is 2257000 J
We are told that the concentration of sodium hypochlorite is 4.0% (w/v). To calculate the molarity of the sodium hypochlorite solution, let us consider a sample volume of 0.1 liter. Since we are given a w/v (Percent of weight of solution in the total volume of solution) value, it means that there are 4 <span>grams of sodium hypochlorite per 100 mL of solution (0.1 liter). Molarity is measured in moles per liter. So we'll just convert the given 4 grams to moles using the molar mass.
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4 grams</span>sodium hypochlorite * (1 mol sodium hypochlorite/ 74.44 g sodium hypochlorite) = 0.054 moles sodium hypochlorite
So we have 0.054 moles sodium hypochlorite / 0.1 L solution
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Thus the molarity is 0.53 mol/L or just 0.53 M.
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